(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
The percent of decrease would be 60%
Answer:
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
Okay! Time to use the Pythagoras theorem.
a^2 + b^2 = c^2
4^2 + 7^2 = x^2
16 + 49 = c^2
65 = c^2
Let's take the square root of both sides to get
c ~ 8.06
C
:)
