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3 years ago

15

(-2-√3) (-2+√3) when simplified is

1 answer:

Ksivusya [100]3 years ago

5 0

Answer:

=1

Step-by-step explanation:

(-2-√3)(-2+√3)

=-2(-2+√3)-√3(-2+√3)

=4-2√3+2√3-√9

=4-3

=1

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Plsssssss helppp ;w;w;

drek231 [11]

<u>Answer:</u>

Given below.

<u>Explanation:</u>

Coordinates given: W( -4, -3 ) , X( 1 , -2 ), Y(2, -7 ) , Z( -3, -8)

To find the distance we will use the formula: distance=√((x2-x1)²+(y2-y1)²)

WX = √((1--4)²+(-2--3)²)

= √26

YZ = √((-3-2)²+(-8--7)²)

= √26

XY = √((2-1)²+(-7--2)²)

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WZ = √(-3--4)²+(-8--3)²

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2 years ago

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Given that D(x) = 2x, select all of the following that are true statements.

GaryK [48]

It is D
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2 years ago

A washer and a dryer cost 634 dollars combined. The washer cost 66 dollars less than the dryer. What is the cost of the dryer?

Nutka1998 [239]

Steps to Solve:

1. 634 / 2 = 317

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3 years ago

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Student Produced Response - Calculator

faltersainse [42]

Answer:

$\dfrac{a}{b}=0.75$ .

Step-by-step explanation:

If two equations $a_1x+b_1y+c_1=0$ and $a_2x+b_2y+c_2=0$ has infinitely many solutions, then

$\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}=\dfrac{c_1}{c_2}$

The given equations are

$ax+by=10$

$3x+4y=20$

It is given that the above system of equations has infinitely many solutions. So,

$\dfrac{a}{3}=\dfrac{b}{4}=\dfrac{10}{20}$

$\dfrac{a}{3}=\dfrac{b}{4}=\dfrac{1}{2}$

Now,

$\dfrac{a}{3}=\dfrac{1}{2}$ and $\dfrac{b}{4}=\dfrac{1}{2}$

$a=\dfrac{3}{2}$ and $b=\dfrac{4}{2}$

$a=1.5$ and $b=2$

So, a=1.5 and b=2.

Now,

$\dfrac{a}{b}=\dfrac{1.5}{2}=0.75$

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3 years ago

Help please now i cant figure it out

12345 [234]

Answer:

a. $\frac{-11}{24}$

b. $\frac{-3}{2} \\$

c. $\frac{31}{7}$

d. $\frac{11}{16}$

11, 3, 31, 11 = code

Step-by-step explanation:

a. $\frac{-1}{6}\\$ * 2 $\frac{3}{4}$ =

2 $\frac{3}{4}$ = $\frac{4*2+3 }{4}$ = $\frac{11}{4}$

$\frac{-1}{6}\\$ * $\frac{11}{4}$ = $\frac{-1*11}{6*4}$ = $\frac{-11}{24}$

b. $\frac{3}{16}$ / $\frac{-1}{8}$ =

$\frac{3}{16}$ * $\frac{8}{-1}$ = $\frac{3*8}{16*-1} \\$ = $\frac{24}{-16}$ = $\frac{-3}{2} \\$

c. $\frac{-31}{56}$ * $\frac{-8}{1}$ = $\frac{31}{7}$ (you can reduce 8 & 56 by dividing by 8: 56/8=7 & -8/8= -1)

d. 1 $\frac{7}{8}$ / 2 $\frac{8}{11}$ =

1 $\frac{7}{8}$ = $\frac{8*1+7}{8}$ = $\frac{15}{8}$

2 $\frac{8}{11}$ = $\frac{11*2+8}{11}$ = $\frac{30}{11}$

$\frac{15}{8}$ * $\frac{11}{30}$ = $\frac{11}{16}$ (you can reduce 15 & 30 by dividing by 15: 15/15=1 & 30/15 = 2)

4 0

3 years ago