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BartSMP [9]
3 years ago
15

Orlando is measuring the angles of a triangle. He measures the first two angles and gets 30° and 70°. What should be the measure

of the third angle?
A) 50°
B) 80°
C) 100°
D) 260°
Mathematics
2 answers:
Andrei [34K]3 years ago
8 0
The answer will be B because all three angles of the triangles add up to180 degrees, and we already know the total of two other angles are 100 degrees, which made the unknown angles have 80 degrees. Hope it help!
Llana [10]3 years ago
7 0

Answer:

B) Third angle  80°.

Step-by-step explanation:

Given  : Orlando is measuring the angles of a triangle. He measures the first two angles and gets 30° and 70°.

To find : What should be the measure of the third angle.

Solution : We have given a triangle

One angle of triangle = 30° .

Second angle of triangle = 70°.

Let the third angle = x .

By the angle sum property : Sum of all the angle of a triangle is 180°.

Then, 30° + 70° + x = 180.

100 ° + x = 180°.

On subtracting both sides by 100

x = 180 - 100.

x = 80 degree.

Therefore, B) Third angle  80°.

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Factor 8x+16y+44 i offered up 15 points
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Find the Greatest Common Factor (GCF)

GCF = 4

Factor out the GCF. (Write the GCF first, then in parenthesis, divide each term by the GCF.)

4(8x/4 + 16y/4 + 44/4)

Simplify each term in parenthesis

<u>= 4(2x + 4y + 11) </u>

4 0
3 years ago
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if 99 certons of milk was sold and 45 of them were regular flavor what is the ratio of chocolate milk sold to regular milk sold+
andreyandreev [35.5K]
Well 99 cartons sold, and 45/99 were normal
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7 0
3 years ago
What would be this answer for the algebra thing
skad [1K]

Answer:

c. 4x + 20 = 140

Step-by-step explanation:

Perimeter = 140 feet

Width = L + 10

P = 2w + 2L

P = 2(L + 10) + 2L

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8 0
2 years ago
b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
4 years ago
2. Check the boxes for the following sets that are closed under the given
son4ous [18]

The properties of the mathematical sequence allow us to find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Addition

   c) AdditionSum

   d) in this case we have two possibilities

       * If we move to the right the addition

       * If we move to the left the subtraction

The sequence is a set of elements arranged one after another related by some mathematical relationship. The elements of the sequence are called terms.

The sequences shown can be defined by recurrence relations.

Let's analyze each sequence shown, the ellipsis indicates where the sequence advances.

a) ... -7, -6, -5, -4, -3

We can observe that each term has a difference of one unit; if we subtract 1 from the term to the right, we obtain the following term

        -3 -1 = -4

        -4 -1 = -5

        -7 -1 = -8

Therefore the mathematical operation is the subtraction.

b) 0. \sqrt{1}. \sqrt{4}, \sqrt{9}, \sqrt{16}, \sqrt{25}  ...

In this case we can see more clearly the sequence when writing in this way

      0, \sqrt{1^2}. \sqrt{2^2}, \sqrt{3^2 } . \sqrt{4^2} , \sqrt{5^2}

each term is found by adding 1 to the current term,

      \sqrt{(0+1)^2} = \sqrt{1^2} \\\sqrt{(1+1)^2} = \sqrt{2^2}\\\sqrt{(2+1)^2} = \sqrt{3^2}\\\sqrt{(5+1)^2} = \sqrt{6^2}

Therefore the mathematical operation is the addition

c)   ... \frac{-10}{2}. \frac{-8}{2}, \frac{-6}{2}, \frac{-4}{2}. \frac{-2}{2}. ...

      The recurrence term is unity, with the fact that the sequence extends to the right and to the left the operation is

  • To move to the right add 1

           -\frac{-10}{2} + 1 = \frac{-10}{2}  -   \frac{2}{2}  = \frac{-8}{2}\\\frac{-8}{2} + \frac{2}{2} = \frac{-6}{2}

  • To move left subtract 1

         \frac{-2}{2} - 1 = \frac{-4}{2}\\\frac{-4}{2} - \frac{2}{2} = \frac{-6}{2}

         

Using the properties the mathematical sequence we find that the recurrence term is 1 and the operation for each sequence is

   a) Subtraction

   b) Sum

   c) Sum

   d) This case we have two possibilities

  •  If we move to the right the sum
  •  If we move to the left we subtract

Learn more here: brainly.com/question/4626313

5 0
3 years ago
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