2, 6, 14, 39, 49, 5, 54, 47, 41, 55, 8, 47, 23, 6 What is the outliers?

Mathematics

1 answer:

bezimeni [28]2 years ago

6 0

Answer:

I think the outliers are 2, 5, 6, and 6. Not sure about 8 though

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Any help? Much appreciated

natulia [17]

Answer:

$\frac{6+\sqrt{27} }{4-\sqrt{3} } = \frac{r+s\sqrt{3} }{13} \\We\ may\ multiply\ the\ numerator\ and\ denominator\ with\ (4+\sqrt{3} ).\\Hence,\\\frac{(6+\sqrt{27})(4+\sqrt{3}) }{13} = \frac{r+s\sqrt{3} }{13} \\Hence,\\24+6\sqrt{3} +4\sqrt{27} +9= r+s\sqrt{3}\\24+6\sqrt{3} +4*3\sqrt{3} } +9= r+s\sqrt{3}\\24+6\sqrt{3} +12\sqrt{3}+9 = r+s\sqrt{3}\\33+18\sqrt{3} = r+s\sqrt{3}\\Hence,\\r=33, s=18$