The sixth term of an arithmetic sequence is 6
<h3>How to find arithmetic sequence?</h3>
The sum of the first four terms of an arithmetic sequence is 10.
The fifth term is 5.
Therefore,
sum of term = n / 2(2a + (n - 1)d)
where
- a = first term
- d = common difference
- n = number of terms
Therefore,
n = 4
10 = 4 / 2 (2a + 3d)
10 = 2(2a + 3d)
10 = 4a + 6d
4a + 6d = 10
a + 4d = 5
4a + 6d = 10
4a + 16d = 20
10d = 10
d = 1
a + 4(1) = 5
a = 1
Therefore,
6th term = a + 5d
6th term = 1 + 5(1)
6th term = 6
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Answer:
31
Step-by-step explanation:
it said 22 2's , so 22 + 9
and 0,1,3,4,5,6,7,8,9 is 9 numbers
Answer:
13.4
Step-by-step explanation:
Answer:
32, 37, 42, 47, 52, 57, 62.
Step-by-step explanation:
It is given that Carissa counts by 5s from 32 to 62.
It means, we have to add 5 in the number to get the next number.
Add 5 in 32.
Now, add 5 in 37.
Similarly, continue the process.
Therefore, the numbers counted by carissa are 32, 37, 42, 47, 52, 57, 62.
ANSWER-the distance is (6,8)
if you set the equation up from 2-8=6 which is your x value and 4-12=8 is your y value it should also give you your Distance between the two points
