now, the circle of the clock has 360°, if we divide it by 60(minutes), we get 360/60, just 6° for each minute.
now, if there are 6° in 1 minute, how many minutes in 95.49°?
well, just 95.49/6 or about 15.92 minutes, I take it you can round it up to 16 minutes.
so 16 minutes since noon, so is about 12:16, about time get the silverware for lunch.
If those two are your only choices then the answer is
none of the above.
<em>Attached is a cumulative frequency table for your data.</em> If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong.
The answer is then none of the above or find one that matches the table attached.
Q-2r=4, therefore: q=4+2r.
Plug the value of q into q+r=37, so you get:
4+2r+r=37
3r=37-4=33
3r=33
Therefore: r=11.
q-2r=4, but r=11, so:
q-2(11)=4
q-22=4
Therefore q=26.
Check if the answer is correct using second equation:
q=4+2r=4+2(11)=4+22=26.
So: q=26 and r=11.
C = 6*P
Use that formula and plug in the x-axis values for P and plot the results (C) on the graph
Answer:
Tina's average speed for the whole journey = 56 kmph
Step-by-step explanation:
Time taken by Sean to travel from Town A to Town B = 4 hours.
Average speed of Sean = 70 km/h
We have equation of motion, s = ut + 0.5 at²
Time, t = 4 hours.
Initial speed, u = 70 km/hr
Acceleration, a = 0 m/s²
Substituting
s = ut + 0.5 at²
s = 70 x 4 + 0.5 x 0 x 4²
s = 280 km
Distance from Town A to Town B = 280 km
Tina took 1 hour more than Sean.
Time taken by Tina to travel from Town A to Town B = 4 +1 = 5 hours
We have equation of motion, s = ut + 0.5 at²
Time, t = 5 hours.
Displacement, s = 280 km
Acceleration, a = 0 m/s²
Substituting
s = ut + 0.5 at²
280 = u x 5 + 0.5 x 0 x 5²
u = 56 km/hr
Tina's average speed for the whole journey = 56 kmph
