All categories

3 years ago

Which of the triangles shown are isosceles triangles?

Mathematics

2 answers:

aalyn [17]3 years ago

5 0

Answer:

Triangle C

Step-by-step explanation:

Hello There!

An isosceles triangle has two congruent sides

Triangle C has two sides that equal 4 therefore triangle C is an isosceles triangle

Triangles A, B and C have no congruent sides therefore they are not isosceles triangles

WITCHER [35]3 years ago

4 0

Answer:

I'm pretty sure that the correct answer here is Triangle C. I think this is the correct answer because an isosceles triangle has two sides that are the same length, and that's what Triangle C represents.

Step-by-step explanation:

Hope that this helps! :)

You might be interested in

The equation |2x-8|+3= 5 has 2 solutions. These

Serggg [28]

Answer: x=8 x=0

Step-by-step explanation:

4 0

3 years ago

Anastasia is grocery shopping with her father and wonders how much shopping is left to do. "We already have 60 percent of the it

Ilia_Sergeevich [38]

Hi

Left to do 40% of the shopping

12 items ⇒ 60% of the items
x items ⇒ 40% of the items

60x = 12(40)
60x = 480
x = 480/60
x = 48/6
x = 8 items

Answer:

Left 8 items of the list (40% of the shopping)

Items: 12+8 = 20 items on her list

4 0

3 years ago

Read 2 more answers

Identify the solution Answer choices 1. 0,3 2. 3, -2 3. 4,2 4 -2,3

Gennadij [26K]

Answer:

2) (3,-2)

Step-by-step explanation:

the solution is where the lines intersect. they intersect at one point because this function is linear. they intersect at the point (3,-2)

5 0

3 years ago

find three consecutive odd integers such that the sum of the middle and largest integer is 21 more than smallest integer.

mina [271]

Answer:

15, 17, 19

Step-by-step explanation:

8 0

3 years ago

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

3 years ago