The net of a square pyramid is shown in the diagram.
2 answers:
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Answer:
x^2/1024 -y^2/7744 = 1
Step-by-step explanation:
The parent hyperbola relation is ...
x^2 -y^2 = 1
This has asymptotes of y = ±x and x-intercepts of ±1.
For the given hyperbola, we want to scale x by a factor of 32, and y by a factor that is 2.75 times that, or 88. Then the equation could be written as ...
(x/32)^2 -(y/88)^2 = 1
More conventionally, the denominator is shown at full value:
x^2/1024 -y^2/7744 = 1
