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2 years ago

What is the GCF of 44j^5k^4 and 121j^2k^6?

Mathematics

2 answers:

Leviafan [203]2 years ago

7 0

$44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\ 121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4$

vampirchik [111]2 years ago

7 0

44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\ 121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4

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The radioactive element americium-241 has a half-life of 432 years. How many years will it take a 10 gram mass of americium-241

geniusboy [140]

<h2>Answer: 816 years</h2>

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u />

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=2.7g$ is the final amount of the material

$A_{o}=10g$ is the initial amount of the material

$t$ is the time elapsed (the quantity we are asked to find)

$h=432y$ is the half life of americium-241

Knowing this, let's find $t$ from (1):

$2.7g=(10g).2^{\frac{-t}{432y}}$

$\frac{2.7g}{10g}=2^{\frac{-t}{432y}}$

$0.27g=2^{\frac{-t}{432y}}$

Applying natural logarithm in both sides:

$ln(0.27g)=ln(2^{\frac{-t}{432y}})$

$-1.309=-\frac{t}{432y}ln(2)$

$-t=\frac{(-1.309)(432y)}{0.693}$

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<u>Finally:</u>

$t=816y$

3 0

3 years ago

Which line has an y-intercept of -2

DiKsa [7]

The y-intercept is found when x is set to 0.

Set x to equal 0 for both equations:

$3(0) - 2y = -6$
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Divide both sides by -2:

$y = 3$

The y-intercept of this equation is 3, so the first line does not have the y-intercept of -2.

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$0 + 2y = -2$
$2y = -2$

Divide both sides by 2:

$y = -1$

The y-intercept of this equation is -1, so the second line does not have the y-intercept of -2.

Neither line has a y-intercept of -2.

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3 years ago

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S_A_V [24]

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3 years ago

Read 2 more answers

The question is below (Giving Brainliest)

WITCHER [35]

Answer:

Hiya there!