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marusya05 [52]
2 years ago
12

What is the GCF of 44j^5k^4 and 121j^2k^6?

Mathematics
2 answers:
Leviafan [203]2 years ago
7 0

44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\  121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4

vampirchik [111]2 years ago
7 0

 44j^5k^4=2^2\cdot11\cdot j^5 \cdot k^4\\  121j^2k^6=11^2\cdot j^2 \cdot k^6\\\\ \text{gcf}( 44j^5k^4 ,121j^2k^6)=11j^2k^4

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Pls solve: 6 - 2/9x = 8
Inga [223]

Answer:

x = -9

Step-by-step explanation:

6 - 2/9x = 8

Subtract 6 from each side

6-6 - 2/9x = 8-6

-2/9 x = 2

Multiply each side by -9/2 to isolate x

-9/2 * -2/9x = 2*-9/2

x = -9

5 0
3 years ago
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How to solve 3+p=8 step by step
AURORKA [14]
3+p=8
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5 0
3 years ago
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Easy I am just not sure on how to solve it please give answer and how I would solve it
Elina [12.6K]

You want to compare the square root of 55 using "mental math". Start off by choosing two perfect squares that you can think of that are close to 55.

If you don't know perfect squares then start with the number 2 and multiply it by itself. 2 times 2 equals 4, so 4 is a perfect square.

Take the number 3, multiply it by itself, and so on. Do this for all the numbers until you find two perfect squares that are close to 55.

The two perfect squares closest to 55 are the square roots of 49 and 64. Find the square root of these numbers.

√49 = 7

√64 = 8

Calculate how far 55 is from 49 and 64. 55 is 6 digits away from 49 and 9 digits away from 64.

This means the square root of 55 will be closer to the square root of 49; 7. Since we know that it will be closer to 7, you can put the less than sign for your answer.

√55 < 7.7

(The actual square root of 55 is ~7.4, so we were correct in determining the answer without using a calculator!)

6 0
2 years ago
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A study was conducted to determine if the salaries of elementary school teachers from two neighboring districts were equal. A sa
Semenov [28]

Answer:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

(–2975, 175)

Do not reject H₀

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the salaries of elementary school teachers are equal in two districts. You can test this trough the population means of the salaries of the teachers if they are either equal or different or directly test if the difference between the salaries of the two districts is cero or not, symbolically: μ₁ - μ₂ = 0

Remember, in the null hypothesis is usually stated the known information, is the "no change" premise and always carries the = symbol.

The hypothesis is:

H₀: μ₁ - μ₂ = 0

H₁: μ₁ - μ₂ ≠ 0

You have two normally distributed variables and you are studying the difference of the means. You can use a pooled Z to make the interval, the formula is:

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Since the test is two-tailed and at a signification level of 5% I've made the interval at the complementary confidence level of 95% so that I can use it to decide over the hypothesis.

X[bar]₁-X[bar]₂ ± Z_{1-\alpha /2}*(√(σ₁²/n₁+σ₂²/n₂)

Z_{1-\alpha /2} = Z_{0,975} = 1,96

[28900-30300 ± 1.96*(√((2300)²/15+(2100)²/15)]

[-1400 ± 1576,15]

[-2976.15;176,15]

Since I've approximated to two decimal units in the intermediate calculations, the values ​​differ slightly, but the interval is:

(–2975, 175)Now, since the 0 is contained in the Confidence interval, the decision is to not reject the null hypothesis. In other words, the difference in average salaries between the two districts is cero.

I hope it helps!

4 0
2 years ago
Which interval notation represent the set of all real numbers greater than 2 and less than or equal to 20
ValentinkaMS [17]
The interval notation for numbers greater than 2 but less than or equal to 20 is (2,20]
6 0
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