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faust18 [17]
3 years ago
9

Determine the error made by Kaleaya. rewrite the solution to show the correct process

Mathematics
2 answers:
Mars2501 [29]3 years ago
6 0
She flipped both of the fractions instead of keeping the first one how it is
fomenos3 years ago
4 0
She flipped both around
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1. Emilo spent 1.45 on 8 apples. What was the cost of one apple? Round to the nearest cent if necessary.
lana [24]

Answer:

1. 18 cent per apple

2. 84

3.$9.10

4. 460 meters

Step-by-step explanation:

1. divide 1.45 by 8 to get price per apple

1.45/8=0.18

2. convert 70% into a decimal

70%=.70

multiply by amount

120(.70)=84

3. convert 20% into a decimal

20%=.20

multiply by amount

45.50(.20)=9.10

4. 1 meter = 100 cm therefore 4.6 meters = 460 cm

8 0
3 years ago
Maddie has x dollars. After spending $90 on a purse, she will have $45. What is the value of x?
julia-pushkina [17]

Add up the values that are known:

90 + 45 = $135

And there u have the answer :)

7 0
4 years ago
Qualitative data is _______.
dybincka [34]
Its data that is Qualitative Instead of Quantative
4 0
3 years ago
Read 2 more answers
Is 3/8 squared irratonal
givi [52]

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3 0
4 years ago
A class survey found that 29 students watched television on Monday, 24 on Tuesday, and 25 on Wednesday. Of those who watched TV
gizmo_the_mogwai [7]

Answer:

There were 49 students in the class

Step-by-step explanation:

To solve this problem, we must build the Venn's Diagram of this set.

I am going to say that:

-The set A represents the students that watched TV on Monday

-The set B represents the student that watched TV on Tuesday.

-The set C represents the students that watched TV on Wednesday.

We have that:

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

In which a is the number of students that only watched TV on Monday, A \cap B is the number of adults that watched TV both on Monday and Tuesday, A \cap C is the number of students that watched TV both on Monday and Wednesday, and A \cap B \cap C is the number of students that watched TV on every day.

By the same logic, we have:

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

C = c + (A \cap C) + (B \cap C) + (A \cap B \cap C)

This diagram has the following subsets:

a,b,c,(A \cap B), (A \cap C), (B \cap C), (A \cap B \cap C)

The sums of all of this values is the number of student that were there in the class. This means that we want to find the value of T:

a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C) = T

We start finding the values from the intersection of three sets.

Solution:

12 students watched TV on all three days:

A \cap B \cap C = 12

14 students watched TV on both Monday and Tuesday

A \cap B + A \cap B \cap C = 14

A \cap B = 14 - 12

A \cap B = 2

Of those who watched TV on only one of these days, 13 choose Monday, 9 chose Tuesday, and 10 chose Wednesday.

a = 13, b = 9, c = 10

29 students watched television on Monday:

A = 29

A = a + (A \cap B) + (A \cap C) + (A \cap B \cap C)

29 = 13 + 2 + (A \cap C) + 12

A \cap C = 29 - 27

A \cap C = 2

24 on Tuesday

B = 24

B = b + (B \cap C) + (A \cap B) + (A \cap B \cap C)

24 = 9 + (B \cap C) + 2 + 12

B \cap C = 24 - 23

B \cap C = 1

Now we have every value needed to find T:

T = a + b + c + (A \cap B) + (A \cap C) + (B \cap C) + (A \cap B \cap C)

T = 13 + 9 + 10 + 2 + 2 + 1 + 12

T = 49

There were 49 students in the class

7 0
4 years ago
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