It sounds like you are setting up the equation below.
(2/5)P = 30
To solve this equation for P, you would multiply both sides of the equation by 5/2.
Answer:
2y+12
Step-by-step explanation:
The entire range of independent variable values is the domain of a function.
After substituting the domain, the range of just a function is the entire set of all possible values for the dependent variable (often y).
What is domain and range?
- The collection of all x-values that can cause the function to "work" and produce actual y-values is known as the domain.
- The range is the set of y-values that are produced when all the conceivable x-values are substituted.
The entire range of independent variable values is the domain of a function.
Keep these things in mind when locating the domain:
- A fraction's denominator (bottom) cannot be 0.
- In this section, the integer following a square root symbol must be positive.
After substituting the domain, the range of just a function is the entire set of all possible values for the dependent variable (often y).
The variety of potential y-values makes up a function's range (minimum y-value to maximum y-value)
- To observe what happens, substitute several x-values into the expression for y.
- Be sure to search for the least and highest y values.
Learn more about Domain and Range here:
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14.42 is your distance formula
(1,0) is the midpoint
if you need the forma for distance it is x2-x1 squared + y2-y1 squared then square root it
