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3 years ago

If possible please try and answer these 3 questions (:

Mathematics

1 answer:

azamat3 years ago

3 0

Answer:

a b c

Step-by-step explanation:

bpommmmmmmmmmmmmmm

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HELP ME PLSSSSSS!!!!!!!

n200080 [17]

Answer:

1) $m\angle x = 35^{\circ}$ , 2) $m\angle x = 60^{\circ}$ , 3) $m \angle x = 40^{\circ}$

Step-by-step explanation:

1) Triangle is a right triangle since tangent line is perpendicular to the radius of the circle. Based on the fact that the sum of internal angles in triangles equals 180°, we find the value of the angle $x$ :

$m\angle x = 180^{\circ} - 90^{\circ} - 55^{\circ}$

$m\angle x = 35^{\circ}$

2) Both triangles are symmetrical right triangles since tangent lines are perpendicular to the two radii and common side is parallel to the third radius. Based on the fact that the sum of internal angles in triangles equals 180°, we find the value of the angle $x$ :

$m \angle x = 180^{\circ} - 90^{\circ} - 30^{\circ}$

$m\angle x = 60^{\circ}$

3) The figure is formed by two symmetrical right triangles. These triangles are right-angled and symmetrical since tangent lines are perpendicular to the two radii and common side is parallel to the third radius. Based on the fact that the sum of internal angles in quadrilaterals equals 360°, we find the value of the angle $x$ :

$m\angle x = 360^{\circ} - 180^{\circ} - 140^{\circ}$

$m \angle x = 40^{\circ}$

4 0

2 years ago

I need help and it is y intercept and x intercept

Neporo4naja [7]

Answer:

y-intercept (0, -3) and x-intercept (3/2, 0)

Step-by-step explanation:

y + 5 =2(x + 1)

y + 5 =2x + 2

subtract 5 from both side

y =2x -3

-3 is the y-intercept because in y=mx+b, b is the y-intercept and it always starts at 0.

To find the x-intercept, we need to plug in 0 for y in y =2x -3

0=2x -3

add 3 to both sides

2x=3

divide both sides by 2

x=3/2 and so the x-intercept is 3/2 and it always starts at 0.

5 0

3 years ago

PLS HELP RIGHT NOW !!!!

Ierofanga [76]

Answer:

1-*8364464737353=kgkdtyry

6 0

2 years ago

Read 2 more answers

Solve for c.<br><br> 3 − 7c − 20c = 7(–7c − 19) + 14c<br><br> c =

OleMash [197]

Answer:

$\boxed{c = -17}$

Step-by-step explanation:

$= > 3 - 7c - 20c = 7( - 7c - 19) + 14c \\ \\ = > 3 - 27c = ( - 7c \times 7) - (7 \times 19) + 14c \\ \\ = > 3 - 27c = - 49c - 133 + 14c \\ \\ = > 3 - 27c = - 35c - 133 \\ \\ = > 3 - 27c + 35c = - 133 \\ \\ = > 3 + 8c = - 133 \\ \\ = > 8c = - 133 - 3 \\ \\ = > 8c = - 136 \\ \\ = > c = - \frac{136}{8} \\ \\ = > c = - 17$

7 0

3 years ago

Read 2 more answers

I can't figure out how to do (i + j) x (i x j)for vector calc

Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

$\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}$

Then, solving the determinant

$\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}$

In our case,

$\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}$

Where we used the formula for AxB to calculate ixj.

Finally,

$\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}$

Thus, (i+j)x(ixj)=i-j

8 0

1 year ago