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Svetach [21]
3 years ago
6

Kai pen for Ruth’s dog is 7 feet long and 6/1.3 feet wide. Her friend Ralph’s dog pen is 14 feet long and 6/1.2 feet wide. How m

any times larger is the area of Ralph’s dog pen?
Mathematics
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

The area of Ralph's dog pen is 2.05 times larger than the area of Ruth's dog pen.

Step-by-step explanation:

Given that the dog pen for Ruth's dog is 7 feet long and 6 / 1.3 feet wide, while her friend Ralph's dog pen is 14 feet long and 6 / 1.2 feet wide, to determine how many times larger is the area of Ralph's dog pen, the following calculation must be performed:

1/3 = 0.333

1/2 = 0.5

7 x 6.333 = X

44,333 = X

14 x 6.5 = X

91 = X

44,333 = 100

91 = X

91 x 100 / 44.333 = X

9,100 / 44,333 = X

205.26 = X

100 = 1

205.26 = X

205.26 / 100 = X

2.05 = X

Thus, the area of Ralph's dog pen is 2.05 times larger than the area of Ruth's dog pen.

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13 would be your answer

Step-by-step explanation:

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3
vlada-n [284]

Answer:

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = 5\frac{1}{4}\ hrs

5\frac{1}{4}\ hrs can be Rewritten as \frac{21}{4}\ hrs

Number of Hours Carl worked on Math project = \frac{21}{4}\ hrs

Number of Hours Sonia worked on Math project = 6\frac{1}{2}\ hrs

6\frac{1}{2}\ hrs can be rewritten as \frac{13}{2}\ hrs

Number of Hours Sonia worked on Math project = \frac{13}{2}\ hrs

Number of Hours Tony worked on Math project = 5\frac{2}{3}\ hrs

5\frac{2}{3}\ hrs can be rewritten as \frac{17}{3}\ hrs.

Number of Hours Tony worked on Math project = \frac{17}{3}\ hrs.

Now Given:

April worked 1\frac{1}{2} times as long on her math project as did Carl.

1\frac{1}{2}  can be Rewritten as \frac{3}{2}

Number of Hours April worked on math project = \frac{3}{2} \times Number of Hours Carl worked on Math project

Number of Hours April worked on math project = \frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs

Also Given:

Debbie worked 1\frac{1}{4} times as long as Sonia.

1\frac{1}{4}  can be Rewritten as \frac{5}{4}.

Number of Hours Debbie worked on math project = \frac{5}{4} \times Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = \frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs

Also Given:

Richard worked 1\frac{3}{8} times as long as tony.

1\frac{3}{8} can be Rewritten as \frac{11}{8}

Number of Hours Richard worked on math project = \frac{11}{8} \times Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = \frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs

Hence We will match each student with number of hours she worked.

        Student                                                            Hours worked

             April.                                                                  7\frac{7}{8} \ hrs

        Debbie.                                                                   8\frac{1}{8}\ hrs

        Richard.                                                                   7\frac{19}{24}\ hrs

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Step-by-step explanation:

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