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Svetach [21]
3 years ago
6

Kai pen for Ruth’s dog is 7 feet long and 6/1.3 feet wide. Her friend Ralph’s dog pen is 14 feet long and 6/1.2 feet wide. How m

any times larger is the area of Ralph’s dog pen?
Mathematics
1 answer:
rusak2 [61]3 years ago
4 0

Answer:

The area of Ralph's dog pen is 2.05 times larger than the area of Ruth's dog pen.

Step-by-step explanation:

Given that the dog pen for Ruth's dog is 7 feet long and 6 / 1.3 feet wide, while her friend Ralph's dog pen is 14 feet long and 6 / 1.2 feet wide, to determine how many times larger is the area of Ralph's dog pen, the following calculation must be performed:

1/3 = 0.333

1/2 = 0.5

7 x 6.333 = X

44,333 = X

14 x 6.5 = X

91 = X

44,333 = 100

91 = X

91 x 100 / 44.333 = X

9,100 / 44,333 = X

205.26 = X

100 = 1

205.26 = X

205.26 / 100 = X

2.05 = X

Thus, the area of Ralph's dog pen is 2.05 times larger than the area of Ruth's dog pen.

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Answer:

8.8 cm

Step-by-step explanation:

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#We substitute the z value in formula to solve X.

z=\frac{\bar  X-\mu}{\sigma}

Where

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z=\frac{\bar  X-\mu}{\sigma}\\\\0.84=\frac{\bar X-8.3}{0.6}\\\\\bar X=0.84\times 0.6+8.3\\\\=8.804\approx 8.8\ cm

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4 years ago
How many solutions does the system of equations have y=5x+7 and 3y-15x=18
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Hello there.

<span>How many solutions does the system of equations have y=5x+7 and 3y-15x=18

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Answer:

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General Formulas and Concepts:

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<u>Algebra I</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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Step-by-step explanation:

Do you mean?

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If so:

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Hypotenuse:

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