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Annette [7]
3 years ago
8

Please help me with this

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
8 0

Answer:

21

Step-by-step explanation:

Hi,

When multiplying this, you can multiply straight across. (Remember 49 can also be written as a fraction, 49/1)

3/7 x 49/1 is equal to 147/7

147/7 is the same thing as 147 divided by 7 which is...

21

Your answer is 21. Hope this helps :)

Slav-nsk [51]3 years ago
7 0

Answer:

21.....

Step-by-step explanation:

hope this helps

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2962

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Find one value of xxx that is a solution to the equation:
alisha [4.7K]

Answer:

-3/2

Step-by-step explanation:

Given the funtion

(2x+3)² - 6x+9 = 0

(2x+3)² = 6x + 9

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4 0
3 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 55 o
Usimov [2.4K]

Answer:

a) For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

b) For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

c) We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

Step-by-step explanation:

For this case our random variable of interest for the weights is bell shaped and we know the following parameters.

\mu = 55, \sigma =6

We can see the illustration of the curve in the figure attached. We need to remember that from the empirical rule we have 68% of the values within one deviation from the mean, 95% of the data within 2 deviations and 99.7% of the values within 3 deviations from the mean.

Part a

For this case and using the empirical rule we can find the limits in order to have 9% of the values:

\mu -2\sigma = 55 -2*6 =43

\mu +2\sigma = 55 +2*6 =67

95% of the widget weights lie between 43 and 67

Part b

For this case we know that 37 is 3 deviations above the mean and 67 2 deviations above the mean since within 3 deviation we have 99.7% of the data then the % below 37 would be (100-99.7)/2 = 0.15% and the percentage above 67 two deviations above the mean would be (100-95)/2 =2.5% and then we can find the percentage between 37 and 67 like this:

100 -0.15-2.5 = 97.85

Part c

We want to find the percentage above 49 and this value is 1 deviation below the mean so then this percentage would be (100-68)/2 = 16%

4 0
4 years ago
What's the answer ?<br><br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B245%20%2B%2044%7D%20" id="TexFormula1" title=" \sq
-Dominant- [34]

\huge\mathfrak\pink{Answer...}

+,- 17

\huge\mathfrak\purple{hope \: it \: helps..}

8 0
3 years ago
Read 2 more answers
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