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Vladimir [108]
3 years ago
7

PLEASEEEEEE HELLPPPPP MEEEEE

Mathematics
1 answer:
NemiM [27]3 years ago
8 0

Answer:

It's A

Step-by-step explanation:

The r coordinate of x is positive 4 which would be the frist number.

The r coordinate of y is positive 1 which would be the second number.

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50+25 POINTS!!! PLZ HELP WILL GIVE BRAINLIEST!!!
frosja888 [35]

3x-2 if x is less an or greater than 1,  will be a negative y value.

-2x+3 when x is greater than 1 will also be a negative y value.


The graph would be the first one ( an upside down V)

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Answer:
C. (1,18)
Explanation
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Locate the point on the line segment between A(3, -5) and B(13, -15) given that the point is 4/5 of the way from A to B. Show yo
SVETLANKA909090 [29]

Answer:

C ( 11 , -11 )

Step-by-step explanation:

Solution:-

We are given two points in the cartesian coordinate system as:

                   A ( 3 , -5 )              B ( 13 , -15 )

The point C lies on the line segment from A to B. The ratio of segment given is:

                              AC / AB = 4 / 5

To solve such type of problems. We will use vector equation of line AC.

To form a vector equation of line representing AB. We will first determine the direction vector ( d ) that is parallel to the line AB as follows:

                 d = OB - OA

                 d = < 13 , -15 > - < 3 , -5 >  

                 d = < 10 , -10 >

The fixed point on the line is taken. We will take point A. The vector equation of line from point A to point B is expressed as:

                < x , y > = OA + s*d

                < x , y > = < 3, -5 > + s* < 10 , -10 >  

The above equation satisfies all the points that lies on the line AB. To determine the coordinates of ( C ). We will plug in the appropriate value of parameter ( s ) and evaluate.

So point C is 4/5 th the magnitude of the distance AB from A. Hence, s = 4/5 as follows:

               < x , y > = < 3 , -5 > + ( 4/5 ) * < 10 , -10 >  

               < x , y > = < 3 , -5 > + < 8 , -8 >  

              < x , y > = < 11 , -11 >   ... Answer

8 0
3 years ago
Use an angle sum identity to derive each double-angle identity.
Simora [160]
\ [cos(2\theta)]'=(2cos^2\theta-1)'=2(cos^2\theta)'-(1)'\\\\=2\cdot2cos\theta\cdot(-sin\theta)-0=-2\cdot2sin\theta cos\theta=\boxed{-2sin2\theta}\\\\Used:\\\ [f(x)-g(x)]'=f'(x)-g'(x)\\\{f[g(x)]\}'=f'[g(x)]\cdot g'(x)\\(cosx)'=-sinx\\sin2x=2sinxcosx
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3 years ago
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Natasha_Volkova [10]

Answer:

see explanation

Step-by-step explanation:

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