it would have to be a, because using pythagorean theorem, we can find that a squared + b squared = c squared. substitute that for 1 + b squared = 4; b squared=3 b = square root of 3
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Pretty sure its true but im a little iffy
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D. 4(a^2)(a^3)/16(b)(b^2)
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101in
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9*5=45
9*4=36
5*4=20
45+36+20=101