Substitute the values into the equation
2(2)+4(-1)-5(1)
4-4-5
-5
(2,2)
(x1+x2)/2, (y1-y2)/2
(-2+6)/2=(2)
(-2+6)/2=2
If triangles AMN and ABC are similar, then
AM/AB = AN/AC
or
AM/(AM + MB) = AN/(AN + NC)
Check if this is true:
AM/AB = 21/(21 + 9) = 21/30 = 7/10
AN/AC = 14/(14 + 6) = 14/20 = 7/10
The angle at vertex A is common to both of the triangles.
Then by the side-angle-side (SAS) similarity theorem, the triangles are indeed similar.
Answer:
(f◦g)(2)
Step-by-step explanation:
The rule is that f(g(x))=(f◦g)(x)
