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LiRa [457]
3 years ago
15

Consider the line =−−8x6y1.

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
6 0

Answer:

Below

Step-by-step explanation:

Well I can't really see the equation but I can tell you how to do it.

Parallel slopes are the same slope as the equation.

For example, y = mx + b

The slope of a line parallel to it is m

Perpendicular slopes are the opposite reciprocal as the equation.

For example, y = mx + b

The slope of a line perpendicular to it is-\frac{1}{m}

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Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2
r-ruslan [8.4K]

Answer:

The value of given expression is \frac{21}{128}.

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

q=1-p=1-\frac{1}{2}=\frac{1}{2}

The given expression is

C(n,x)p^xq^{n-x}

It can be written as

^nC_xp^xq^{n-x}

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}

\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}

\frac{7!}{2!5!}(\frac{1}{2})^{2+5}

\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}

21(\frac{1}{2})^{7}

\frac{21}{128}

Therefore the value of given expression is \frac{21}{128}.

7 0
3 years ago
Дешовок в гавне собак гандонов свиней)))))))))) xddddddd
Readme [11.4K]

Step-by-step explanation:

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8 0
2 years ago
Read 2 more answers
150% of 66(Need the work shown)
ANTONII [103]
66 is the 100%
we can solve this problem by the rule of three.

Therefore:
66------------------------100%
x--------------------------150%

x=(66 * 150%) / 100%=99

Answer 150% of 66 is 99.

Other method:
150% of 66=1.5 *66=99

Answer: 150% of 66 is 99.
4 0
3 years ago
Read 2 more answers
What is the solution to the equation?<br><br> 9.1k = 63.7
Natalija [7]

Answer:

k = 7

Step-by-step explanation:

9.1k = 63.7

/9.1     /9.1

k = 7

Check your answer:

9.1k = 63.7

9.1 (7) = 63.7

63.7 = 63.7

This statement is true.

Hope this helps!

4 0
2 years ago
Read 2 more answers
Suppose that scores on the mathematics part of a test for eighth-grade students follow a Normal distribution with standard devia
riadik2000 [5.3K]

Answer:

We need an SRS of scores of at least 153.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large an SRS of scores must you choose?

This is at least n, in which n is found when M = 20, \sigma = 150. So

M = z*\frac{\sigma}{\sqrt{n}}

20 = 1.645*\frac{150}{\sqrt{n}}

20\sqrt{n} = 1.645*150

\sqrt{n} = \frac{1.645*150}{20}

\sqrt{n} = 12.3375

(\sqrt{n})^{2} = (12.3375)^{2}

n = 152.2

Rounding to the next whole number, 153

We need an SRS of scores of at least 153.

8 0
3 years ago
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