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Zarrin [17]
2 years ago
13

What will be the new position of the given point (9,-4) after reflection across the y axis

Mathematics
2 answers:
ludmilkaskok [199]2 years ago
6 0

Answer:

9

Step-by-step explanation:

9

kow [346]2 years ago
6 0

Answer:

(-9,-4)

Step-by-step explanation:

(9,-4) is in the 4th quadrant and if u reflect over the y axis the will be in the 3rd quadrantand quadrant 3's points can only be negative negative  

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Si tienes un rectángulo de área igual a x2 + 5x¿Cuál de las siguientes factorizaciones nos presenta el producto de la base por l
Softa [21]

Answer: factorizar x de x ^ 2 + 5x.

x (x + 5)

Step-by-step explanation:

7 0
2 years ago
Consider the following system of equations:
ivolga24 [154]
The answer is x=-15 and y=25

8 0
3 years ago
A polynomial function has a zero at 4 (multiplicity 3) and 0 (multiplicity 1). Write a function in standard form that can repres
VLD [36.1K]

Answer:

(x^4) - 64x

Step-by-step explanation:

zeros at 4 and 0 are the roots so can be factor as x*(x-4) and the multiplicity tels to what power you have to raise those factors

x^{1} *(x-4)^{3} becuase multiplicity of 1 for root at 0, and multiplicity of 3 at root 4

now to write this in standard form

x*(x-4)^{3} = \\x*(x-4)(x^{2} +4x+16)= \\(x^{2} -4x)(x^{2} +4x+16) = \\x^{4} +4x^{3} +16x^{2} -4x^{3} -16x^{2} -64x = \\x^{4} -64x

8 0
2 years ago
Help math math math ASAP
STALIN [3.7K]
<h3><u>Solution</u>:-</h3>

The equation of any straight line can be written as in slope intercept form as -

\green{ \underline { \boxed{ \sf{y=mx+c}}}}

where,

  • m is its slope
  • c is its y-intercept.

<em><u>Given equation:- </u></em>

\begin{gathered}\\\implies\quad \sf 5x+y = 10 \\\end{gathered}

<u>Arranging it in slope intercept form by transposing 5x to RHS </u>

\begin{gathered}\\\implies\quad \sf y = 10 -5x \\\end{gathered}

\begin{gathered}\\\implies\quad \sf y =  -5x +10\\\end{gathered}

\leadstoComparing the equation y = -5x +10 with the standard form of the equation, we get -

\quad \bull\: \sf m= -5

\quad \bull \: \sf c= 10

Thus , 5 is our required answer.

4 0
2 years ago
Read 2 more answers
Jill arranges quarters in stacks of increasing powers of 2, starting with the zeroth power (20). If she ends up with six stacks,
Ratling [72]
Stack 1 : 2^0 = 1 quarter.
Stack 2 : 2^1 = 2 quarters.
Stack 3: 2^2 = 4 quarters.
Stack 4: 2^3 = 8 quarters.
Stack 5 : 2^4 = 16 quarters.
Stack 6: 2^5 = 32 quarters.
1 + 2 + 4 + 8 + 16 + 32 = 63
Answer: She used 63 quarters. 
8 0
3 years ago
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