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KatRina [158]
3 years ago
5

Solve using systems of equations. -3x-4y=-8 3x+3y=9

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0
Sure thing!

-3x-4y=-8\\
 3x+3y=9\\
----------\\
0x-1y=1\\
y=-1\\



since y = -1 we can just plug it into the first equation
-3x-4(-1)=-8\\
-3x+4=-8\\
-3x=-12\\
x=4
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MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD
Varvara68 [4.7K]

Answer:

\sf \: Proved \: \angle \: OAD  \:  =  \angle \: OCD

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u>\angle \: OAD  \:  =  \angle \: OCD</u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

\angle \: OBD  \:  =  \angle \: OCD

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

\angle \: OBD  \:  =  \angle \: OAB \\ \angle \: OAB  \:  =  \angle \: OAD (same \: angles) \\ \angle \: OBD  \:  =  \angle \: OAD

Consider above prove as statement B

From Statement A & B we can say that

\angle \: OAD  \:  =  \angle \: OCD

<em>Thanks for joining brainly community!</em>

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2 years ago
0.36 as a standard form
NemiM [27]

Answer:

<h3>0.36 x 10⁰</h3>

Step-by-step explanation:

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2 years ago
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