Remember for any two polygons
Area of polygons is directly proportional to square of sides
So
- BC²/XY²=135/15
- 15²/XY²=9
- (15/3)²=XY²
- XY=5in
#35
- HJ²/XY²=168/378
- 8²/XY²=0.44
- XY²=64/0.44
- XY²=145.45
- XY\approx 12+
I think the answer will be 7.25.
Answer:
We can easily simplify the expression by using a computational tool
The expression is
"6 x squared minus 54 x plus 84 over quantity 8 x squared minus 40 x plus 48 divided by quantity x squared plus x minus "
Please, see attached images below, for a full explanation
A)

= 10 * 10 * 10 = 1,000
It is not A
B)

= 10 * 10 * 10 * 10 = 10,000
It is not B
C)

= 10 * 10 * 10 * 10 * 10 = 100,000
It could be C
D)

= 10 * 10 * 10 * 10 * 10 * 10 = 1,000,000
It is not D
Your answer is C)
Hope I helped!
Answer:
5536 calculators
Step-by-step explanation:
We integrate the function dx/dt to obtain the number of new calculators between beginning of the 3rd week and end of week 4. Note that beginning of 3rd week is the same as end of 2nd week. So,
=
Let u = t + 12, then
= 1. So, du = dt. We also change the limits of our integration. So, when t = 2, u = 2 + 12 = 14 and when t = 4, u = 4 + 12 = 16
Then
= ∫₁₄¹⁶
₁₄¹⁶ = ![5000[16 + \frac{100}{16} - (14 + \frac{100}{14} )] = 5000 [16 - 14 + \frac{100}{16} - \frac{100}{14} ] = 5000 [2 + \frac{100}{16} - \frac{100}{14} ] = 5535.7](https://tex.z-dn.net/?f=5000%5B16%20%2B%20%5Cfrac%7B100%7D%7B16%7D%20-%20%2814%20%2B%20%5Cfrac%7B100%7D%7B14%7D%20%29%5D%20%3D%205000%20%5B16%20-%2014%20%2B%20%5Cfrac%7B100%7D%7B16%7D%20-%20%5Cfrac%7B100%7D%7B14%7D%20%20%5D%20%3D%205000%20%5B2%20%2B%20%5Cfrac%7B100%7D%7B16%7D%20-%20%5Cfrac%7B100%7D%7B14%7D%20%20%5D%20%3D%205535.7)
≈ 5536 calculators