Please help on at least 2 of these!! I'll give brainliest!!

navik [9.2K]

Using PEMDAS, we know that we must solve what’s in the perentheses first so: 25/5 + 7 - (4x3) = 25/5 + 7-12. Next, we simplify 25/5 because that is division so now it is 5+7-12. Now you add 7 to 5 to get 12 and then subtract 12 so your answer is now zero.

7 0

2 years ago

7. Use graph paper to graph each linear function: f(x) = 4x - 7

skelet666 [1.2K]

Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.

5 0

2 years ago

Giving out 60 points

Yuki888 [10]

If the markers are 4.5 inches away on the map, and 2.5 inches represents 10 miles, then we need to make ratios we can work with.

Inches / Miles:

4.5 / x
2.5 / 10

Now, we can cross multiply to end up with:

2.5 * x = 4.5 * 10

Simplify:

2.5x = 45

Divide 2.5 on each side:

2.5x / 2.5 = 45 / 2.5

Simplify:

x = 45 / 2.5
x = 18

Awesome! Now we have a real ratio on the real distance of the markers.

2.5 : 10 & 4.5 : 18.

18 miles is the actual distance between the two markers.

Hope I could help! If my math is wrong, or it isn't the answer you are looking for, please let me know!
Have a good one!

6 0

3 years ago

Fulton Gardens buys 6,300 flower bulbs. If 70 bulbs can be planted in each flower bed, how many flower beds are needed to plant

ki77a [65]

Answer:

90

Step-by-step explanation:

6300/70=90

6 0

3 years ago

How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used

MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the n-th term of the sequence, a (n), is given recursively by

• a (1) = 1

• a (n) = a (n - 1) + 21 … … … for n > 1

We can find the explicit rule for the sequence by iterative substitution:

a (2) = a (1) + 21

a (3) = a (2) + 21 = (a (1) + 21) + 21 = a (1) + 2×21

a (4) = a (3) + 21 = (a (1) + 2×21) + 21 = a (1) + 3×21

and so on, with the general pattern

a (n) = a (1) + 21 (n - 1) = 21n - 20

Now, we're told that the sum of some number N of terms in this sequence is 2332. In other words, the N-th partial sum of the sequence is

a (1) + a (2) + a (3) + … + a (N - 1) + a (N) = 2332

or more compactly,

$\displaystyle\sum_{n=1}^N a(n) = 2332$

It's important to note that N must be some positive integer.

Replace a (n) by the explicit rule:

$\displaystyle\sum_{n=1}^N (21n-20) = 2332$

Expand the sum on the left as

$\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332$

and recall the formulas,

$\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n$

$\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2$

So the sum of the first N terms of a (n) is such that

21 × N (N + 1)/2 - 20N = 2332

Solve for N :

21 (N ² + N) - 40N = 4664

21 N ² - 19 N - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

N = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer N for which the first N terms of the sum add up to 2332.

4 0

2 years ago