The volume of the larger cone is equal to the total volume of the two smaller cones
<h3>How to compare both cones?</h3>
From the question, we have two equal cylinders.
This means that the cylinders have equal volume.
From the complete question, a large cone is placed in one of the cylinders, while two small cones are placed in the other.
Since the cylinders have equal volumes, then the volume of the large cone equals the sum of the volumes of the smaller cones.
Hence, the volume of the larger cone is equal to the total volume of the two smaller cones
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The number of pieces of 1/3 foot tall to make a 6 feet skyscraper is 18 pieces.
The model of a skyscraper comes in pieces and each piece is 1/3 feet tall.
After all the pieces are put together the skyscraper is 6 feet tall.
We have to calculate how many pieces were put together to make the 6 feet skyscraper.
Let X be the number of pieces put together to make a 6 feet skyscraper.
Now,
Each piece = 1/3 feet tall.
Since all the pieces together make 6 feet tall, we can write the number of pieces needed to make 6 feet tall as:
X x (1/3) = 6
X = 6 x 3 = 18
Thus, we need 18 pieces of 1/3 foot tall to make a 6 feet skyscraper.
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Answer:
<h2>245,600,000,000</h2>
Step-by-step explanation:
245 Billion, 600 Million, Thousand, Hundreds
Hope this helps! <3
Hello, please consider the following.
![\displaystyle \begin{aligned} \int\limits^x {5sin(5t)sin(t)} \, dt &= -\int\limits^x {5sin(5t)} \, d(cos(t))\\ \\&=-[5sin(5t)cos(t)]+ \int\limits^x {25cos(5t)cos(t)} \, dt\\\\&=-5sin(5x)cos(x)+ \int\limits^x {25cos(5t)} \, d(sin(t))\\ \\&=-5sin(5x)cos(x)+[25cos(5t)sin(t)]+ \int\limits^x {25sin(5t)sin(t)} \, dt\\\\&=-5sin(5x)cos(x)+25cos(5x)sin(x)+ \int\limits^x {(25*5)sin(5t)sin(t)} \, dt\end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7D%20%5Cint%5Climits%5Ex%20%7B5sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%20%26%3D%20-%5Cint%5Climits%5Ex%20%7B5sin%285t%29%7D%20%5C%2C%20d%28cos%28t%29%29%5C%5C%20%5C%5C%26%3D-%5B5sin%285t%29cos%28t%29%5D%2B%20%5Cint%5Climits%5Ex%20%7B25cos%285t%29cos%28t%29%7D%20%5C%2C%20dt%5C%5C%5C%5C%26%3D-5sin%285x%29cos%28x%29%2B%20%5Cint%5Climits%5Ex%20%7B25cos%285t%29%7D%20%5C%2C%20d%28sin%28t%29%29%5C%5C%20%5C%5C%26%3D-5sin%285x%29cos%28x%29%2B%5B25cos%285t%29sin%28t%29%5D%2B%20%5Cint%5Climits%5Ex%20%7B25sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%5C%5C%5C%5C%26%3D-5sin%285x%29cos%28x%29%2B25cos%285x%29sin%28x%29%2B%20%5Cint%5Climits%5Ex%20%7B%2825%2A5%29sin%285t%29sin%28t%29%7D%20%5C%2C%20dt%5Cend%7Baligned%7D)
And we can recognise the same integral, so.
And then,
Thanks
