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Basile [38]
3 years ago
13

Please Help Me I Rally Need The Awnser

Mathematics
1 answer:
Flura [38]3 years ago
7 0

Answer:

64

Step-by-step explanation:

if regular x =116

then plug it in 116-52=64

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Joelle ordered 12 dozen doughnuts for the honor roll
Serjik [45]

Answer:

The answer is there are 30 glazed donuts

Step-by-step explanation:

there are 12 donuts to a dozen therefore 12 * 12 = 144 donuts all together.

donuts with chocolate icing

144 \times  \frac{3}{8}  = 54

with white icing and sprinkles

144 \times \frac{1}{4}  = 36

donuts with pink icing

144 \times  \frac{1}{6}  = 24

Total donuts minus donuts with icing equal glazed donuts

144 - 54 - 36 - 24 = 30

7 0
2 years ago
Write n+6 in a word phase
Delvig [45]
The sum of a number and 6.

Or

The sum of n and 6
7 0
3 years ago
Find the domain of the function:<br><br> V(X)= the square root of 9+X
stellarik [79]

Answer:

[-9,∞)

Step-by-step explanation:


3 0
3 years ago
Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used
ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes  head start

Senn needs to give Ms. Beetle 18.4 minutes  head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes  head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0
3 years ago
consider the following data: **** please view photo*** what’s wrong with the scatter plot that is suppose to represent the data
nordsb [41]
The increments are not the same, therefore the graph shows misleading data, you could fix it by changing the increments of the x variable on the x axis to 1 so it shows accurate data
5 0
3 years ago
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