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3 years ago

PLEASE HELP!THANK YOU!

Mathematics

1 answer:

blondinia [14]3 years ago

7 0

Answer:

can you please clarify your question? and it would be y=mx+b

b is you flat rate and m is per mile

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Which graph represents -9x+4y≤8?

yulyashka [42]

The awnser is C!!!!!

8 0

2 years ago

Quick!!!!!!!!!!!!!!!

Degger [83]

Answer: discrete.

Step-by-step explanation:

Discrete variable

It is a variable whose value is evaluated by counting.

Example: Number of books published in a month.

Continuous variable

It is a variable whose value is evaluated by measuring ( not countable).

Example: Distance: 1.52 m

Since the number of dental visits a randomly chosen person had for the past 5 years is a countable.

here, Variable: Let X =number of dental visits a randomly chosen person had for the past 5 years

So, the random variable described is discrete.

7 0

2 years ago

The cost of renting a car is $35/wk plus $0.25/mi traveled during that week. An equation to represent the cost would be

algol [13]

$48.75 minus $35 would equal 13.75 then you divide by 0.25 that would give you 55 so M=55

3 0

3 years ago

(D^2 +2D +1)y=e^-x log(x) solve using method variation of parameter?

Ad libitum [116K]

First you'll need the complementary solutions. The characteristic equation for this ODE is

$D^2+2D+1=(D+1)^2=0\implies D=-1$

with multiplicity 2. This means two linearly independent solutions will be $y_1=e^{-x}$ and $y_2=xe^{-x}$ .

Via variation of parameters, the particular solution will take the form

$y_p=y_1u_1+y_2u_2$

where

$u_1=-\displaystyle\int\frac{y_2e^{-x}\log x}{W(y_1,y_2)}\,\mathrm dx$
$u_2=\displaystyle\int\frac{y_1e^{-x}\log x}{W(y_1,y_2)}\,\mathrm dx$

The Wronskian is

$W(y_1,y_2)=\begin{vmatrix}e^{-x}&xe^{-x}\\-e^{-x}&e^{-x}(1-x)\end{vmatrix}=e^{-2x}(1-x)+xe^{-2x}=e^{-2x}$

So, you have

$u_1=-\displaystyle\int\frac{xe^{-x}e^{-x}\log x}{e^{-2x}}\,\mathrm dx$
$u_1=-\displaystyle\int x\log x\,\mathrm dx$
$u_1=\dfrac14x^2-\dfrac12x^2\log x$

and

$u_2=\displaystyle\int\frac{e^{-x}e^{-x}\log x}{e^{-2x}}\,\mathrm dx$
$u_2=\displaystyle\int\log x\,\mathrm dx$
$u_2=x(\log x-1)$

So the solution to the ODE is

$y=C_1y_1+C_2y_2+y_1u_1+y_2u_2$
$y=(C_1+C_2x)e^{-x}+\left(\dfrac14x^2-\dfrac12x^2\log x\right)e^{-x}+(\log x-1)x^2e^{-x}$
$y=(C_1+C_2x)e^{-x}+\dfrac14x^2e^{-x}(2\log x-3)$

3 0

3 years ago

A bag contains pennies, nickels, dimes, and quarters. There are 50 coins in all. Of the coins, 8% are pennies and 40% are d

diamong [38]

Answer:

Step-by-step explanation:

number of

pennies=8 % of 50=8/100×50=4

dimes=40 % of 50=40/100×50=20

nickels=4+3=7

quarters=50-(4+20+7)=50-31=19

total money=4+20×10+7×5+19×25

=4+200+35+475

=714 pennies

=7.14 $

6 0

3 years ago