3 years ago

PLEASE HELP!THANK YOU!

Mathematics

1 answer:

blondinia [14]3 years ago

7 0

Answer:

can you please clarify your question? and it would be y=mx+b

b is you flat rate and m is per mile

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what is the altitude corresponding to the side of length 8.5 CM in a parallelogram whose area is 34 CM square

Crazy boy [7]

Area = length of base × altitude
34 = 8.5 × a
34 = 8.5a
a = 34/8.5
a = 4

The altitude of the corresponding side is 4 cm

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3 years ago

Solve the system of equations Y= -7x+3 Y= -x -3 What is X What is Y

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Given that the measure of angle 6 is 1/8 of measure of angle 4. Find the measures of these two angles if a∥b.

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Answer:

see explanation

Step-by-step explanation:

Let ∠4 be x then ∠6 is $\frac{1}{8}$ x

∠4 and ∠6 are same side interior angles and are supplementary, thus

x + $\frac{1}{8}$ x = 180

Multiply through by 8 to clear the fraction

8x + x = 1440, that is

9x = 1440 ( divide both sides by 9 )

x = 160

Hence ∠4 = 160° and ∠6 = 160° ÷ 8 = 20°

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3 years ago

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Jasper's lawn is 3/4 of an acre in size. The fertilizer bag states that 5 1/2 bags are required for 1 acre. How many bags does J

Nady [450]

Answer: $4\dfrac{1}{8}\ \text{bags}$

Step-by-step explanation:

Given

Jasper lawn is three-fourth of an acre

1 acre of land requires $5\frac{1}{2}$ bags

convert mixed numeral to fraction

$\Rightarrow 5\dfrac{1}{2}=\dfrac{11}{2}$

$\therefore 1\ \text{acre}\equiv\dfrac{11}{2}\ \text{bags}\\\\\Rightarrow \dfrac{3}{4}\ \text{acre}\equiv \dfrac{11}{2}\times \dfrac{3}{4}=\dfrac{33}{8}\ \text{bags}$

$\Rightarrow \dfrac{33}{8}\ \text{bags}=4\dfrac{1}{8}\ \text{bags}$

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False. Btw this is a computer and technology question not a mathematic question

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