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Neporo4naja [7]
3 years ago
14

This table shows values that represent a quadratic function. What is the average rate of change for the quadratic function for t

he interval from x = 4 to x = 6? 

Mathematics
1 answer:
Oxana [17]3 years ago
5 0
I think D. But don’t trust me if your still not sure
Have a good day
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O'Farrell offers 2 different after school clubs. The Ukulele club has 30 students and attendance is increasing by 6 students per
Bond [772]
Month 6, work down below

months / students
0 30 45
1 36 48
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8 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST Find the coordinates of the points of intersection of the graphs with coordinate axes: c y=− 1/4 x+2
Neko [114]

Answer:

the y intercept is (0,2) and x intercept is (8,0)

Hope this helps

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3 years ago
Solve the equation. -3x^2+2x=8
daser333 [38]
The answer is 1+2√23 or 1-2√23
4 0
4 years ago
Riley is also making boxes to hold baseballs. She wants the dimensions of her boxes
Sergio039 [100]

The volume of the box is 105 cubic units.

<h3>What is volume of cuboid ?</h3>

The amount of space inside a cuboid is calculated using the term "cuboid volume." Having length, breadth, and height, the cuboid is a three-dimensional shape. A shape with a certain length, breadth, and height will be obtained if we start with a rectangular sheet and keep stacking them. Length x Width x Height is the formula for calculating the cuboid's volume.

Given that : The dimensions of her boxes to be 4 x 6 x 3 units.

The volume of cuboid=7×5×3=105 cubic units.

so ,The volume of the box is 105 cubic units.

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4 0
1 year ago
PLS help me with thisss:((((((​
lara31 [8.8K]

Answer:

C and B

Step-by-step explanation:

(6)

\frac{3x-7y}{8} × \frac{6}{3x-7y} ← cancel 3x - 7y on numerator and denominator

= \frac{1}{8} × \frac{6}{1} = \frac{6}{8} = \frac{3}{4} → C

(7)

\frac{6x}{x^2-9} ÷ \frac{8}{4x-12}

Factorise the denominators of both fractions

x² - 9 = x² - 3² = (x - 3)(x + 3) ← difference of squares

4x - 12 ← factor out 4 from each term

= 4(x - 3)

Then rewrite as

\frac{6x}{(x-3)(x+3)} ÷ \frac{8}{4(x-3)} ← cancel 8 and 4 by 4

= \frac{6x}{(x-3)(x+3)} ÷ \frac{2}{x-3}

• leave first fraction, change ÷ to × , turn second fraction ' upside down'

= \frac{6x}{(x-3)(x+3)} × \frac{x-3}{2} ← cancel x - 3 on numerator and denominator

= \frac{6x}{x+3} × \frac{1}{2} ← cancel 2 and 6 on numerator and denominator

= \frac{3x}{x+3} → B

8 0
3 years ago
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