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lbvjy [14]
3 years ago
13

Given:

Mathematics
1 answer:
otez555 [7]3 years ago
8 0

Answer:

the question is incorrectly written. please rewrite the question.

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0.368 written in expanded form
andrew-mc [135]
.3 + .06 + .008 = 0.386

Hope I Helped:P 
8 0
3 years ago
Is (3, 1) a solution to this system of equations? 13x + 17y = 12 x + 7y = 19
mr Goodwill [35]

Answer:

No, (3, 1) is not a solution to this system.

Step-by-step explanation:

13x+17y=12

x+7y=19

-----------------

13(3)+17(1)=39+17=56, not 12

3+7(1)=3+7=10, not 19

3 0
3 years ago
Select the equation in which the slope equals 11 and the y-intercept equals -2.
kirill115 [55]

Answer: y=11x-2


Step-by-step explanation:

1. By definition, the equation of the line has the following form:

y=mx+b

Where <em>m</em> is the slope and <em>b</em> is the y-intercept.

2. Keeping the information above on mind, you the problem says that the slope is 11 and the y-interecept is -2, then:

m=11\\b=-2

3. Substitute these values into the equation of the line and you obtain that the equation of that line is:

y=11x-2


7 0
3 years ago
Read 2 more answers
From an 8 foot board, a carpenter sawed off one piece that was 2 3/4 feet long and another piece that was 3 1/2 feet long . How
Butoxors [25]
<span>After the two cuts, 1 3/4 ft of the board is left.</span><span> </span>
7 0
3 years ago
Read 2 more answers
Two gears are adjusted so that the smaller gear drives the larger one. if the smaller gear of 3.7cm rotates through an angle of
zepelin [54]

Answer:

<em>The larger gear will rotate through 156°</em>

Step-by-step explanation:

<u>Arc Length</u>

The arc length S of an angle θ on a circle of radius r is:

S = \theta r

Where θ is expressed in radians.

The smaller gear of r1=3.7 cm drives a larger gear of r2=7.1 cm. The smaller gear rotates through an angle of θ1=300°.

Convert the angle to radians:

\displaystyle \theta_1=300*\frac{\pi}{180}=\frac{5\pi}{3}

The arc length of the smaller gear is:

\displaystyle S_1=\frac{5\pi}{3}\cdot 3.7

\displaystyle S_1=\frac{18.5\pi}{3}

The larger gear rotates the same arc length, so:

\displaystyle S_2=\frac{18.5\pi}{3}

\displaystyle \theta_2\cdot r_2=\frac{18.5\pi}{3}

Solving for θ2:

\displaystyle \theta_2=\frac{18.5\pi}{3r_2}

\displaystyle \theta_2=\frac{18.5\pi}{3*7.1}

\theta_2=2.73\ radians

\displaystyle \theta_2=2.73*\frac{180}{\pi}=156

The larger gear will rotate through 156°

7 0
3 years ago
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