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lbvjy [14]
3 years ago
13

Given:

Mathematics
1 answer:
otez555 [7]3 years ago
8 0

Answer:

the question is incorrectly written. please rewrite the question.

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Compare 2/5 and 1/10. what is the denominator
omeli [17]
1/5 five being the denominator, because in math you must always simplify
7 0
3 years ago
Read 2 more answers
A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra
Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em />cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

Step-by-step explanation:

Given

P\ (a,b)

r = \± \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

r = \sqrt{(a)^2 + (b)^2}

Since a belongs to the x axis and b belongs to the y axis;

cos\theta is calculated as thus

cos\theta = \frac{a}{r}

Substitute r = \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}

cos\theta = \frac{a}{\sqrt{a^2 + b^2}}

Rationalize the denominator

cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}

cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

3 0
3 years ago
Which number line represents the solution set for the inequality 1x24?
coldgirl [10]

Answer:

2 should be the correct one.

3 0
3 years ago
Please answer this correctly
ira [324]

Answer:

Surface area = 804m^2

5 0
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Suppose you own a car that gets 35 miles per
SSSSS [86.1K]

Answer:

$30

Step-by-step explanation:

840/35 = 24 gallons

24*1.25 = 30 dollars

7 0
2 years ago
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