All categories

3 years ago

(d) Nigel measures out 30 grams from a 1 kilogram bag of sugar.

Mathematics

2 answers:

Brut [27]3 years ago

8 0

Answer:

Step-by-step explanation:

1kg = 1000g

30÷1000 × 100 = 0.03×100=3%

Gwar [14]3 years ago

4 0

Answer:

0.003%

Step-by-step explanation:

1000g = 1kg

30g = 0.003kg

You might be interested in

The glee club needs to raise money for the spring trip to Europe, so the members are assembling holiday wreaths to sell. Before

Ksju [112]

Answer:

5 pinecones on the deluxe wreath and 4 pinecones on the regular wreath

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Land's Bend sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the intern

Naya [18.7K]

Answer:

80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ( $\mu_1-\mu_2$ ) is [-9.132 , 23.332].

Step-by-step explanation:

We are given that a random sample of 7 sales receipts for mail-order sales results in a mean sale amount of $81.70 with a standard deviation of $18.75.

A random sample of 11 sales receipts for internet sales results in a mean sale amount of $74.60 with a standard deviation of $28.25.

Firstly, the Pivotal quantity for 80% confidence interval for the difference between population means is given by;

P.Q. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ~ $t__n__1-_n__2-2$

where, $\bar X_1$ = sample mean sales receipts for mail-order sales = $81.70

$\bar X_2$ = sample mean sales receipts for internet sales = $74.60

$s_1$ = sample standard deviation for mail-order sales = $18.75

$s_2$ = sample standard deviation for internet sales = $28.25

$n_1$ = size of sales receipts for mail-order sales = 7

$n_2$ = size of sales receipts for internet sales = 11

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2} +(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(7-1)\times 18.75^{2} +(11-1)\times 28.25^{2} }{7+11-2} }$ = 25.11

<em>Here for constructing 80% confidence interval we have used Two-sample t test statistics as we don't know about population standard deviations.</em>

<em />

So, 80% confidence interval for the difference between population means, ( $\mu_1-\mu_2$ ) is ;

P(-1.337 < $t_1_6$ < 1.337) = 0.80 {As the critical value of t at 16 degree

of freedom are -1.337 & 1.337 with P = 10%}

P(-1.337 < $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < 1.337) = 0.80

P( $-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ${(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}$ < $1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.80

P( $(\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ < ( $\mu_1-\mu_2$ ) < $(\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ) = 0.80

<u>80% confidence interval for</u> ( $\mu_1-\mu_2$ ) =

[ $(\bar X_1-\bar X_2)-1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ , $(\bar X_1-\bar X_2)+1.337 \times {s_p\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } }$ ]

= [ $(81.70-74.60)-1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }$ , $(81.70-74.60)+1.337 \times {25.11 \times \sqrt{\frac{1}{7} +\frac{1}{11} } }$ ]

= [-9.132 , 23.332]

Therefore, 80% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases ( $\mu_1-\mu_2$ ) is [-9.132 , 23.332].

4 0

3 years ago

-4c+5d = 14<br> -40+ 3d= 8

solmaris [256]

Answer:

d = 3 c= 1/4

Step-by-step explanation:

Eq. 1) -4c + 5d = 14

Eq. 2) -4c + 3d = 8 ( the written Eq. says 40 but I am guessing it's 4c )

subtract Eq. 1 and Eq. 2

2d=6

d=3

plug 3 in for d in Eq. 1

-4c + 5(3) = 14

-4c + 15 = 14

-4c = -1

c = 1/4

6 0

3 years ago

A building worth $829,000 is depreciated for tax purposes by its owner using the straight-line depreciation method.

Delvig [45]

The value of the building would be $699,400 in 4 years.

<h3>What will be the value of the building?</h3>

Depreciation is the when the value of an asset reduces as a result of wear and tear. Straight line depreciation is a method used in depreciating the value of an asset linearly with the passage of time.

The equation that can be used to determine the value of the building with a straight line depreciation is:

Value of the asset = initial value of the asset - (number of months x deprecation rate)

y = 829,000 - 2700x

The first step is to determine the number of months it would take for the building to have a value of $699,400.

$699,400 = 829,000 - 2700x

829,000 - 699,400 = 2,700x

129,600 = 2,700x

x = 129,600 / 2,700

x = 48 months

Now convert, months to years

1 year = 12 months

48 / 12 = 4 years

To learn more about depreciation, please check: brainly.com/question/11974283

#SPJ1

8 0

1 year ago

What are all the rational roots of the polynomial f(x) = 20x4 x3 8x2 x Ă˘â‚¬"" 12?.

pav-90 [236]

The rational roots of the polynomial given in the question are -4/5 and 3/4.

Given-

Given polynomial function is,

$20x^4+x^3+8x^2+x-12$

The given polynomial function has the four-degree equation in which the greatest power of the variable is four. Suppose one root of <em>x </em>is 1 to solve it further. So one factor is,

$x-1$