Well, we know that it costs $60 plus 5 per month for Alpha Fitness Club.
We also know that it costs $20 plus 10 per month for Omega Fitness Club.
In order to find out which one would cost the most, we must add the additional costs to the original join cost.
(NEVER add the join cost, just do the join cost at the beginning or else the clubs will never become the same cost.)
Club M1 M2 M3 M4 M5 M6 M7 M8 M9
Alpha: 60 65 70 75 80 85 90 95 100
Omega:20 30 40 50 60 70 80 90 100
If you look above, you realize that there is a time when they both cost the same.
Summary sentence:
After 9 months, the cost to belong to either fitness club would be $100.
20% decreased and it needs to increase 40,000 more to get To its normal value
Multiply all terms in the first equation by 2 and all terms in the second by 3.
You should obtain:
6x + 16y = 34
-6x + 27y = 9
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43y =43, and so y = 1. Subbing 1 for y in the first eq'n, we get
3x + 8(1) = 17, or 3x = 9, or x = 3.
The solution is (3, 1).
Answer:
See answers below
Step-by-step explanation:
From the given functions, the equivalent function for when x = 0 is -(x-1)²
h(x) = -(x-1)²
h(0) = -(0-1)²
h(0)= -(-1)²
h(0) = -1
when x = 2, the equivalent function is -1/2x - 1
h(x) = -1/2x - 1
h(2) = -1/2(2) - 1
h(2) = -1-1
h(2) = -2
when x = 5, the equivalent function is -1/2x - 1
h(x) = -1/2x - 1
h(5) = -1/2(5) - 1
h(5) = -5/2-1
h(5) = -7/2
Answer:
9) 51 × 10⁻⁵ = 0.00051
10) Cash price = #54,000 × (1 - 0.125) = #47,250
11) -40·p·q÷(-2)² = -10·p·q
12) 0.003 × 0.045 = 1.35 × 10⁻⁴
13) N40°W = 320°
14) The base diameter of the cylinder = √(4 × (700×π cm³/7)/π) = 20 cm
15) The LCM of 2·x²·y, 3·x·y² is 12·x²·y²
16) 636,000 = 6.36 × 10⁵
17) 1/3·π·r²·h₁ = π·r²·h₂
h₂/h₁ = 1/3·π·r²/( π·r²) = 1/3
h₂/12 = 1/3
h₂ = 12/3 = 4 cm, the height of the cylinder = 4 cm
18) The angle = 180 + 45 = 225°
19) The total surface area = 22/7×14²/4 + 22/7 ×14 × 20 = 1034 cm²
20) The number is 58/2 = 29.
Step-by-step explanation: