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Sergeu [11.5K]
3 years ago
12

So basically I need help

Mathematics
1 answer:
vovangra [49]3 years ago
7 0
Um- thats hard OH YOU WANT 20 CHARACTERS ILL GIVE YOU 20 CHARACTERS STOP SAYING THAY
You might be interested in
Could someone help me plz i know it's easy one but i couldn't do it
Luden [163]
1. is 5 seconds
2. would be about 105 because is goes a tiny bit over 100
5 0
3 years ago
Use the Pythagorean Theorem to find the length ​
WINSTONCH [101]

Answer:

10

Step-by-step explanation:

64 +36=100

Square root of 100 is 10

3 0
3 years ago
Converse of Pythagorean theorem, Find the missing side length of each triangle round to the nearest 10th if necessary.
torisob [31]

The formula for the Pythagorean theorem is,

\text{Hypotenuse}^2=Opposite^2+Adjacent^2

8 0
1 year ago
Evaluate the polynomial 6x - y for x= -3 and Y=2.<br> A.15 <br> B. -20<br> C.4<br> D.-16
ra1l [238]
I think the answer is B.
6(-3)=-18, and y=2
so 6x-y=-18-2=-20
6 0
3 years ago
A recent study found that the average length of caterpillars was 2.8 centimeters with a
pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

\mu = 2.8, \sigma = 0.7.

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{4 - 2.8}{0.7}

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0
2 years ago
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