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3 years ago

Find the Perimeter of the figure below, composed of a rectangle and two semicircles.

Mathematics

1 answer:

qwelly [4]3 years ago

7 0

Answer:

61.42 units

Step-by-step explanation:

Perimeter = sum of all sides of surrounding the figure = circumference of a circle + 2(length of the rectangle)

Note: two semicircles = 1 full circle

Perimeter = πd + 2(L)

Where,

Diameter of the circle (d) = 10

Length of rectangle (L) = 15

Plug in the values

Perimeter = π*10 + 2(15)

Perimeter = 10π + 30

≈ 61.42 units (approximated to nearest tenths)

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The area of a triangle is 15x^4+3x^3+4x^2-x-3 square meters. The length of the base of the triangle is 6x^2-2 meters. What is th

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Answer:

The height of the triangle is: $H = (5x^2 + x +3)$

Step-by-step explanation:

Here, the area the triangle is given as: $15x^4 + 3x^3 + 4x^2 - x - 3$

Also, base of the triangle = $(6x^2 -2)$

Let us assume the height of the triangle = H units

Now, AREA of TRIANGLE = $\frac{1}{2} \times B \times H$

$\implies (15x^4+3x^3+4x^2-x-3 ) = \frac{1}{2} \times ( 6x^2-2) \times H\\\implies H =\frac{ (15x^4+3x^3+4x^2-x-3 )}{(3x^2-1)}$

Solving by LONG DIVISION, we get:

$H = (5x^2 + x +3)$

Hence, the height of the triangle is: $H = (5x^2 + x +3)$

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