Answer:
D) 5.6, 6, 6, 1
Step-by-step explanation:
Before we start solving this problem, we need to first rearrange the provided data from smallest to greatest, so we get:
5, 5, 5, 5, 6, 6, 6, 6, 6
now we can find the mean. The mean is nothing but the average of the provided values, so we need to add them and then divide them into the total amount of data:
next, in an odd number of data, the median is the middle number when written in order. In this case the middle number (the one in the position 5) is 6, so:
median=6
the mode will tell you what is the value that has the greatest number of occurrencies. This is the number that appears the most on our list.
Mode=6
and the range is the difference between the greatest value and the smallest value:
Range=6-5=1
so the answer is D.
Let's begin by listing the first few multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44. So, between 1 and 37 there are 9 such multiples: {4, 8, 12, 16, 20, 24, 28, 32, 36}. Note that 4 divided into 36 is 9.
Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:
<span>How many multiples of 4 are there in {n; 37< n <101}? We could list and then count them: {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval. Try subtracting 40 from 100; we get 60. Dividing 60 by 4, we get 15, which is 1 less than 16. So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:
1000
-40
-------
960
Dividing this by 4, we get 240. Adding 1, we get 241.
Finally, subtract 9 from 241: We get 232.
There are 232 multiples of 4 between 37 and 1001.
Can you think of a more straightforward method of determining this number? </span>
Answer:
D. 
Step-by-step explanation:
We are given the graph of the transformed tangent function.
As, we can see that the graph is shifted 2 units upwards.
That is, the parent function is translated 2 units up.
So, the new function will be of the form, 
.
Thus, options A and C are not correct.
Moreover, 'If a function f(x) has period P, then the function cf(bx) will have period 
.
Also, form the figure, we see that the period of the graphed function is 
.
Since, 
have period .
So, function in option B will have period 
, which is not possible.
<em>Further, function in option D have period .</em>
Thus, the equation of the graphed function is, .
Answer:
Step-by-step explanation:
The associative property is helpful while adding or multiplying multiple numbers. By grouping, we can create smaller components to solve. It makes the calculations of addition or multiplication of multiple numbers easier and faster. Here, adding 17 and 3 gives 20.
the identity property of 1 says that any number multiplied by 1 keeps its identity. In other words, any number multiplied by 1 stays the same. The reason the number stays the same is because multiplying by 1 means we have 1 copy of the number.
