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3 years ago

Who know the answer to this?

Mathematics

1 answer:

melomori [17]3 years ago

4 0

Answer: A (w=2a+3)

Step-by-step explanation: The answer is A because for every week after the tiger is born it gains 2 pounds. that's the w=2a part. The +3 is there because the tiger started with 3 pounds.

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What is the slope of a line that is parallel to the line whose equation is ax+by=c?

miskamm [114]

Answer:

-a/b

Step-by-step explanation:

ax+by=c

First get the equation in slope intercept form ( y= mx+b where m is the slope and b is the y intercept)

Subtract ax from each side

ax+by -ax=-ax +c

by = -ax+c

Divide each side by b

by/b = -ax/b + c/b

y = -a/b * x + c/b

The slope is -a/b and the y intercept is c/b

We want the line parallel so it has the same slope, -a/b

3 0

3 years ago

Read 2 more answers

In x-5=9, the correct way to isolate the variable is to

den301095 [7]

Answer: x=14

Step-by-step explanation:

Add 5 to both sides to get the x alone and get your answer.

8 0

3 years ago

What is the greatest common factor of 20a^2 12a^2 and 8a

olchik [2.2K]

Answer:

Step-by-step explanation:

8 0

3 years ago

The cost of producing magnets with the company logo printed on them consists of aonetime setup fee of $180,00 plus $0.60 for eac

MissTica

We have the following:

The formula to calculate the cost is as follows:

$C=180+0.6\cdot p$

In this case, p is equal a 1700, replacing:

$\begin{gathered} C=180+0.6\cdot1700 \\ C=180+1020 \\ C=1200 \end{gathered}$

Therefore, the cost of 1700 magnets is $1200

6 0

2 years ago

Differentiate Vx(x + 2) with respect to x.

Travka [436]

Answer:

$y'= \frac{3x+2}{2\sqrt{x} }$

General Formulas and Concepts:

Calculus

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

$y=\sqrt{x} (x+2)$

Step 2: Rewrite

$y=x^{\frac{1}{2} } (x+2)$

Step 3: Differentiate

Product Rule [Basic Power/Chain Rule]: $y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)$
Simplify: $y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}$
Rewrite: $y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}$
Add: $y'= \frac{3x+2}{2\sqrt{x} }$

7 0

3 years ago