3 years ago

What is the sum of the exterior angles of a 14-gon?

Mathematics

2 answers:

Zanzabum3 years ago

5 0

Answer:

360 degrees.

Step-by-step explanation:

The sum of exterior angles of every polygon is 360 degrees so the What is the sum of the exterior angles of a 14-gon is also equal to 360 degrees.

ad-work [718]3 years ago

4 0

Answer:

360 degrees

Step-by-step explanation:

The sum of all exterior angles in any convex polygon is 360 degrees.

You might be interested in

Last week Karen spent $121.35 on food for her family. She only has $200 to spend every two weeks. How much does hse have left to

yan [13]

Answer:

$78.65

Step-by-step explanation:

take 200-121.35=78.65

$78.65

5 0

3 years ago

Read 2 more answers

A survey of 100,000 adults found that 5% of Americans walk to work. Which of the following could be used to simulate the results

aalyn [17]

Answer:

A I think im fairly certain

Step-by-step explanation:

3 0

2 years ago

Ally works in a shop for $18 per hour dependent

meriva

Independent is hour
Dependent is her rate ($18) because it DEPENDS on how long she works

3 0

2 years ago

Elimination method: ax+by=r, -bx+cy=s

Alex17521 [72]

$\left[\begin{array}{ccc}ax+by=r\\\\-bx+cy=s\end{array}\right]$

Isolate x for $ax+by=r$

$x= \frac{r-by}{a} ; a \neq 0$

Subsititute $x= \frac{r-by}{a}$

$-b \frac{r-by}{a} +cy=s$

Isolate r for : $-b \frac{r-by}{a}+cy=s$

$r=- \frac{as-acy-b^2y}{b} ; a \neq 0;b \neq 0$

For x : $\frac{r-by}{a}$

Subsititute r = $- \frac{as-acy-b^2y}{b}$

$x= -\frac{as-acy-b^2y}{b}/a$

$x = \frac{cy-s}{b}$

The solutions to the system of equations are:

$r= -\frac{as-acy-b^2y}{b}$ and <span> $x = \frac{cy-s}{b}$
</span>
hope this helps!

3 0

2 years ago

Help plz thank you lots

Galina-37 [17]

False
X is the output, and y is the input

6 0

2 years ago