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IgorLugansk [536]
2 years ago
15

Solve the equation 5w-5+4w-4

Mathematics
1 answer:
Licemer1 [7]2 years ago
8 0
The answers 9w-9, do you need to show your work?
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Keep in mind significant figures. 6.020*0.0510=?
xeze [42]

Answer:

3.072×10^-1

Step-by-step explanation:

please mark me as brainlest

7 0
2 years ago
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Macy is painting a design that contains two repeating patterns. One pattern repeats every 8 inches. The other repeats every 12 i
Firlakuza [10]
The pattern will be at the same place at 2 feet, 4 feet, 6 feet, 8 feet, 10 feet, 12 feet, 14 feet, 16 feet, and 18 feet
5 0
3 years ago
Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t
dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: (x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14

<u>Area of the big rectangle</u>: (x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99

The difference is: 11x+85

( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

f(d)=h=-2d^2+7d+4

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

f(0)=h=-2(0)^2+7(0)+4

h=4

The height is 4 meters.

b) 9 meters.

For d=1

f(1)=h=-2(1)^2+7(1)+4

f(1)=h=-2+7+4

h=9

b) The ball travels 4 meters.

But to calculate it, it is when h=0

0=-2d^2+7d+4

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

V=\pi r^2h

V=\pi (2.5)^2 \cdot 5

V=31.25 \pi

V_{c} \approx 98.17 \text{ m}^3

The volume of the sphere:

$V=\frac{4}{3}  \pi r^2$

V_{s} \approx 65.4 \text{ m}^3

The volume of the capsule is approximately 163.57  \text{ m}^3

3 0
3 years ago
Please help i need an A
Basile [38]

Answer:

(1) 820

(2) 1920

Step-by-step explanation:

(1) solving 20 x 41, using associative property.

20 * 41  = (2 x 10) x 41  = 2 x (10 x 41)

             = 20 x 41         = 2 x 410

             = 820              =  820

(2) distribute 32 as 30 + 2 and solve.

     60 x 32

  = 60 x (30 + 2) = 60(30) + 60(2)

                        = 1800 + 120

                        = 1920

             

3 0
3 years ago
Which sequence of transformations on △ABC will result in a figure that is congruent to △ABC?
solong [7]

Answer: A.) c is -1 -2 b is -4 -2 a is -3 -3

Step-by-step explanation: sry but thats all i know i hoped i helped a lil bit :)

3 0
3 years ago
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