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2 years ago

Find the cosine of ∠I.

Mathematics

1 answer:

denis-greek [22]2 years ago

7 0

Answer:

$\sqrt{\frac{3}{5} } .$

Step-by-step explanation:

1) cos(I)=IH/IG;

$2) \ IG=\sqrt{IH^2+GH^2} =10;$

$3) \ cos(I)=\frac{2\sqrt{15}}{10}=\frac{\sqrt{15}}{5}=\sqrt{\frac{3}{5}}.$

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What property was used on 14k + 2 (3k+5) -5 = 10 to obtain 14k + 6k +10 - 5 =10

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3 years ago

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3 years ago

The sum of three numbers is 141. The first number is 9 more than the third. The second number is 4 times the third. What are the

Advocard [28]

Answer:

x...third number

4x...second number

x-9...first number

(x)+(4x)+(x-9)=141

x+4x+x-9=141

6x-9=141

Let's add 9 to both sides...

9+6x-9=141+9

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Let's divide both sides by 6...

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Let's check our work...

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