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3 years ago

I GIVEEEEEEEEEEEEEEEEEEEEEE BRAINLISSSSSSSSSSSST

Mathematics

1 answer:

Kitty [74]3 years ago

8 0

Answer:

I see two triangles

Step-by-step explanation:

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3cis(5pi/4) in polar form

madreJ [45]

Rectangular form:
z = -2.1213203-2.1213203i

Angle notation (phasor):
z = 3 ∠ -135°

Polar form:
z = 3 × (cos (-135°) + i sin (-135°))

Exponential form:
z = 3 × ei (-0.75) = 3 × ei (-3π/4)

Polar coordinates:
r = |z| = 3 ... magnitude (modulus, absolute value)
θ = arg z = -2.3561945 rad = -135° = -0.75π = -3π/4 rad ... angle (argument or phase)

Cartesian coordinates:
Cartesian form of imaginary number: z = -2.1213203-2.1213203i
Real part: x = Re z = -2.121
Imaginary part: y = Im z = -2.12132034

8 0

2 years ago

(The question is in the picture)<br> Thank you I’ll really appreciate it !! I really need this !

GREYUIT [131]

Do you have any formula ?

5 0

3 years ago

What is the mass of an object that has a density of 1.3 g/cm3 and a volume

tangare [24]

Answer:

The mass of the object is 2.6 grams

Step-by-step explanation:

The density of an object is the ratio between its mass and its volume

The equation of the is d = $\frac{m}{V}$ , where

m is the mass

V is the volume

Let us use this equation to solve the question

∵ An object has a density of 1.3 g/cm³

∴ d = 1.3 g/cm³

∵ Its volume is 2 cm³

∴ V = 2 cm³

→ Substitute them in the equation of the denisty above

∵ 1.3 = $\frac{m}{2}$

→ Multiply both sides by 2

∴ 2 × 1.3 = 2 × $\frac{m}{2}$

∴ 2.6 = m

∴ The mass of the object is 2.6 grams

8 0

2 years ago

At 12 noon, leslie recorded the temperature as 56 degrees f. The temperature had increased by 8 degrees f from 10am. The tempera

Marat540 [252]

Let the temperature at 10am be x, then
x + 8 = 56
x = 56 - 8 = 48 degrees F

Let y be the temperature at 8am, then
y - 2 = 48
y = 48 + 2 = 50 degrees.

4 0

3 years ago

Read 2 more answers

Solve this equation using the radical equation method

Yuki888 [10]

The domain:
$3x+6\geq0\ \ |-6\\3x\geq-6\ \ \ |:3\\x\geq-2\\\\D:x\in\left< -2;\ \infty\right)$

$2x=\sqrt{3x+6}-1\ \ \ |+1\\\\2x+1=\sqrt{3x+6}\ \ \ \ |^2\\\\(2x+1)^2=\left(\sqrt{3x+6}\right)^2\ \ \ |use:\ (a+b)^2=a^2+2ab+b^2\\\\(2x)^2+2\cdot2x\cdot1+1^2=3x+6\\\\4x^2+4x+1=3x+6\ \ \ \ |-3x-6\\\\4x^2+x-5=0\\\\4x^2-4x+5x-5=0\\\\4x(x-1)+5(x-1)=0\\\\(x-1)(4x+5)=0\iff x-1=0\ \vee\ 4x+5=0\\\\x=1\ \vee\ 4x=-5\\\\x=1\in D\ \vee\ x=-1.25\in D$

$Answer:\ \boxed{x=-1.25\ \vee\ x=-1}$

6 0

3 years ago