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Rama09 [41]
3 years ago
14

I eat a third of a box of chocolates there are not 16 left how many were in the box at the start?

Mathematics
2 answers:
daser333 [38]3 years ago
5 0
If you ate a third of the box and there ARE 16 left then you started with 48 originally
hammer [34]3 years ago
4 0
You started with 48 because u ate a third of it and you said 16 there fore there is 48
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What is the area of the triangle?<br> 9 4 12
LUCKY_DIMON [66]

Answer:

  13.636

Step-by-step explanation:

The area can be found using Heron's formula:

  A = √(s(s-a)(s-b)(s-c))

where s=(a+b+c)/2.

For the given triangle, ...

  a=9, b=4, c=12, s=(9+4+12)/2 = 12.5

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The area of the triangle is about 13.636 square units.

7 0
3 years ago
The line x - y = 5 passes through<br> (-5, 0)<br> (0, 5)<br> (0, -5)
neonofarm [45]

The line x - y = 5 passes through the point (0, -5)

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3 years ago
Read 2 more answers
The Z-score is based on the concept of the normal distribution, the fact that we can expect 95% of the values in the distributio
Dennis_Churaev [7]

Answer:

C.) In perfect health.

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7 0
3 years ago
Which of the following triangles are right triangles? select all apply
Alex Ar [27]

Answer:

The following Triangles are Right Triangles:

1.  Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

2. Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

3. Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

Step-by-step explanation:

For a Triangle to be a Right Triangle it must Satisfy Pythagoras theorem.

i.e.

(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}

For Δ ABC Where AB = 76 in, BC = 357 in, and AC = 365 in.

AC² = 365² = 133225

AB² + BC² = 76² + 357² = 1333225

∴  AC² = AB² + BC²

Hence Δ ABC a Right Triangle.

For Δ MIT Where MI = 123 cm, IT = 836 cm, and MT = 845 cm.

MT² = 845² = 71405

MI² + IT² = 123² + 836² = 714025

∴ MT² = MI² + IT²

Hence Δ MIT a Right Triangle.

For  Δ MEL Where ME = 20 ft, EL = 99 ft, and ML = 101 ft.

ML² = 101² = 10201

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∴ ML² = ME² + EL²

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7 0
3 years ago
Math the number to the value of its 5
Ugo [173]
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133,533 = 500
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