All categories

2 years ago

I eat a third of a box of chocolates there are not 16 left how many were in the box at the start?

Mathematics

2 answers:

daser333 [38]2 years ago

5 0

If you ate a third of the box and there ARE 16 left then you started with 48 originally

hammer [34]2 years ago

4 0

You started with 48 because u ate a third of it and you said 16 there fore there is 48

You might be interested in

A. Sin40=6/x B. Sin40= x/6 C. Cos40= x/6 D. Cos40=6/x

STatiana [176]

The answer is A. sin40=6/x

7 0

3 years ago

16^3x+8^x+6 Could you please give me the steps as well for this problem?

BARSIC [14]

Answer:

x = 2

Step-by-step explanation:

$16^{3x} = 8^{x+6} \\2^{4(3x)} = 2^{3(x+6)} -->$ (16 = $2^{4}$ and 8 = $2^{3}$ )

$2^{12x} = 2^{3x+18}$

Since the base number is 2, the exponents must equal each other.

So:

12x = 3x+18

9x = 18

x = 2

8 0

2 years ago

HELP ME PLEASEEEE HELPPPPPPPPPPPP

mario62 [17]

Answer:

y / cos x

Step-by-step explanation:

Use trigonometry to help

cos = adjacent side/hypotenuse
hypotenuse = adjacent side / cos

Substitute values:

Distance between the Sun and the Moon = y / cos x

7 0

2 years ago

Lucy wants to be exempt from her semester exam. In order for that to happen, she has to average an 85 over 3 test grades. Her fi

anastassius [24]

Answer:

Grades to be scored in 3rd exam = 88

Step-by-step explanation:

Given that average of 3 numbers is 85.

First two numbers are 81 and 86.

To find:

3rd number so that average is 85

Solution:

Let the third number = $x$

Formula for average is:

$Average = \dfrac{Sum\ of\ numbers}{Total\ count\ of\ numbers}$

Here, sum of numbers = $81+86+x =167+x$

Total count of numbers = 3

$85 = \dfrac{167+x}{3}\\\Rightarrow x=255-167\\\Rightarrow \bold{x=88}$

Grades to be scored in 3rd exam = 88

8 0

2 years ago

Find the value of this expression if x = 5

vfiekz [6]

Answer:

-16

Step-by-step explanation:

5^2+7/5-7

32/-2

-16

8 0

2 years ago

Read 2 more answers