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Rama09 [41]
3 years ago
14

I eat a third of a box of chocolates there are not 16 left how many were in the box at the start?

Mathematics
2 answers:
daser333 [38]3 years ago
5 0
If you ate a third of the box and there ARE 16 left then you started with 48 originally
hammer [34]3 years ago
4 0
You started with 48 because u ate a third of it and you said 16 there fore there is 48
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zvonat [6]

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Find the discriminant and the numbers of real roots for this equation: 4x^2+12x+9=0
Len [333]

Answer:

D=0

The quadratic equation has one real root with a multiplicity of 2.

Step-by-step explanation:

Given a quadratic equation:

 ax^2+bx+c=0

You can find the Discriminant with this formula:

D=b^2-4ac

<em> </em>In this case you have the following quadratic equation:

4x^2+12x+9=0

Where:

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Therefore, when you substitute these values into the formula, you get that the discriminant is this:

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8 0
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antiseptic1488 [7]

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SOVA2 [1]

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So the largest number less than 999 that can fit some 24s into it with no space left over is (41 x 24) = 984 .

Did this help?

Brainly, thank you, rating are all appreciated! Miss Hawaii : )

4 0
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5/100=

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