Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form
is equal to

where
The <u>discriminant</u> of the <u>quadratic equation</u> is equal to

if
----> the <u>quadratic equation</u> has two <u>real roots</u>
if
----> the <u>quadratic equation</u> has one <u>real root</u>
if
----> the <u>quadratic equation</u> has two <u>complex roots</u>
in this problem we have that
the <u>discriminant</u> is equal to 
so
the <u>quadratic equation</u> has two <u>complex roots</u>
therefore
the answer is the option A
There are two complex roots
For this, we will be using Triangle Angle Sum Theorem (all interior angles in a triangle add up to 180°) for Triangle BCD. Since Angle CBD and BDC are congruent to each other and Angle BDA, we can solve for those two angles to get that angle. Our equation will look like this:
Firstly, subtract 35 on both sides of the equation: 
Next, divide both sides by 2 and your answer will be 72.5 = x.
Since Angle CBD and BDC are 72.5°, this means that Angle BDA is 72.5° as well.
So we are given two points, say P1(4,7), P2(x,19).
Slope is given by
m=3=(y2-y1)/(x2-x1)=(19-7)/(x-4)
solve for x
3=(19-7)/(x-4)
cross multiply
3(x-4)=12
3x-12=12
3x=12+12=24
x=8
Answer:

Explanation:
Just multiply 62 and 53 to get 3286.
I am joyous to assist you at any time.
Step-by-step explanation:
Each interior angle=140°
(n-2)180°/n=140°
180°n-360°/n=140°
180°n-360°=140°n
180°-140°=360°
40°n=360°
n=360°/40°
n=9
Hence, the number of sides of the polygon is 9.
It is nonagon .