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Dahasolnce [82]
2 years ago
6

Help please!! I'll name you brainliest!!

Biology
1 answer:
Ulleksa [173]2 years ago
7 0

Answer:

ok :)

Explanation:

1. T

2. T

3. F

4. T

5. F

6. T

7. T

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In the activated sludge process, air and bacteria are added to the incoming sewage.
STALIN [3.7K]

The answer is true. It is because the activated sludge process made use of the aeration in which air being mixed with a substance together with a bacteria and protozoa that is in a biological floc that will help treat the wastewater. 

6 0
3 years ago
In a particular population of mice, certain individuals display a phenotype called "short tail," which is inherited as a dominan
WARRIOR [948]

Answer:

The "short tail" dominant allele is easier to eliminate by selective breeding.

Explanation:

The only way for a recessive allele to be expressed (be visible) is when it appears as recessive homozygotic. These means the organisms need to have 2 copies of the gene. Selective breeding is based on the characteristics that one can see, so if the organism shows the "dilute" phenotype you can keep reproducing this individuals and get rid of the dominant allele.

On the other hand if you have a population with the dominant phenotype, you discard all the ones that have a recessive trait and you breed the dominant phenotype you could still get individuals with the recessive phenotype and individuals that express the dominant phenotype but are heterozygous.

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3 years ago
What contains dissolved carbon?<br><br> A- Atmosphere<br> B- Sinks<br> C- Oceans and lakes
alekssr [168]
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3 0
3 years ago
How will scientists know if a patient is cured from HIV
omeli [17]

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8 0
3 years ago
A man and a woman are both carriers for two autosomal recessive disorders, PKU (chromosome 12) and cystic fibrosis (chromosome 7
ValentinkaMS [17]

Answer:

Pr= (3/16)

Explanation:

It was stated that both the man and the woman are both carriers for two autosomal recessive disorders, PKU (chromosome 12) and cystic fibrosis (chromosome 7).

∴ let Aa¹Bb° represent the traits in the Man

Where;

Aa¹ = carrier of PKU

Bb° = carrier of cystic fibrosis

Also, let Cc¹Dd° represent the traits in the woman

Where;

Cc¹ = carrier of PKU

Dd° = carrier of cystic fibrosis

Now, if Aa¹Bb° self-crossed, we'll have the F1 progeny as AB, Ab° , a¹B and a¹b°

also, if Cc¹Dd° self-crossed, we have CD, Cd° , c¹D and c¹d° as their F1 progeny

In the F2 generation, the dihybrid cross between the F1 generations will be:

AB, Ab° , a¹B, a¹b°    × CD, Cd° , c¹D, c¹d°

ACBD, ACb°D, a¹CBD, a¹Cb°D

ACBd°, ACb°d°, a¹CBd°, a¹Cb°d°

Ac¹BD, Ac¹b°D, a¹c¹BD, a¹c¹b°D

Ac¹Bd°, Ac¹b°d°, a¹c¹Bd°, a¹c¹b°d°

Only (a¹CBD, Ac¹BD, a¹c¹BD)  shows the probability that she will have PKU but not CF.

6 0
3 years ago
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