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3 years ago

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1 answer:

artcher [175]3 years ago

5 0

The answer is A because the square root function needs to be greater than or equal to zero bc the circle is filled and you can’t have a negative radical. It’s also choice A because the -1 is outside of the radical which means it’s being translated downwards from the parent function. Hope that helps ;-;

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Answer:

5/9 miles

Step-by-step explanation:

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2 years ago

Which is the graph of the following equation?

lesantik [10]

Given equation is

$\frac{(x-5)^2}{16} - \frac{(y-2)^2}{9}=1$

The given equation is in the form of

$\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2}=1$

a^2= 16 , so a=4

b^2 = 9 so b= 4

The value of 'a' is greater than the value of 'b'

So it is a Horizontal hyperbola

First two graphs are horizontal hyperbola

Here center is (h,k)

h= 5 and k =2 from the given equation

So center is (5,2)

Now we find vertices

Vertices are (h+a,k) and (h-a,k)

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So vertices are (9,2) and (1,2)

Second graph having same vertices and center

The correct graph is attached below

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3 years ago

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2 years ago

If the original quantity is 8 and the new quantity is 4, what is the percent decrease

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3 years ago

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The width of a photo is 5 inches less than its length. A border of 2 inches is placed around the photo. The area covered by the

DaniilM [7]

Answer:

Dimensions of photo excluding border:

x = 11 inches

y = 6 inches

Step-by-step explanation:

Let the length be 'x' and width be 'y'.

The width of a photo is 5 inches less than its length, that is:

x-5 = y

let 'X' be length of photo including border and 'Y' be the width of photo including border:

Where X = x+2 and Y = y+2

Now , we have X-5 = Y

and X*Y = 104 square inches

*putting Y = X-5*

X(X-5) = 104

$X^2 - 5X - 104 = 0$

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$X(X-13)+8(X-13) = 0\\(X-13)(X+8)$

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Hence X = 13 or X = -8

As length can not be negative, X = 13 inches

Y = X-5 = 13-5 = 8 inches

Dimensions of photo excluding border:

x = X - 2 = 13-2 = 11 inches

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3 years ago