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3 years ago

Write the equation of the line that passes through the points (-2, -8) and (8,-8).

Mathematics

1 answer:

shepuryov [24]3 years ago

5 0

Answer:

slope is 0

y-(-8)=0(x-(-2))

y+8=0(x+2) no solution

Step-by-step explanation:

$\frac{-8-(-8)}{8-(-2)} =0/10$

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Simplify (3a^4b^3)^3

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Answer:

Step-by-step explanation:

(3a^4b^3)^3

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=27a^12b^9

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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4 years ago

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Step-by-step explanation:

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4 years ago

which statements are true about the graph of the function f(x) = 6x – 4 x2? check all that apply. the vertex form of the functio

Brut [27]

Answer:

The vertex of the function is the point $(-3,-13)$

The graph increase over the interval--------> (-3,∞)

Step-by-step explanation:

we have

$f(x)=6x-4+x^{2}$

1) Convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+4=x^{2}+6x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)+4+9=x^{2}+6x+9$

$f(x)+13=x^{2}+6x+9$

Rewrite as perfect squares

$f(x)+13=(x+3)^{2}$

$f(x)=(x+3)^{2}-13$ -----> function in vertex form

2) Find the vertex

The vertex of the function is the point $(-3,-13)$

3) Find the axis of symmetry

we know that

In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex

The x-coordinate of the vertex in this problem is equal to $x=-3$

therefore

the equation of the axis of symmetry is $x=-3$

4) Find the increase-decrease intervals

The graph increase over the interval--------> (-3,∞)

The graph decrease over the interval--------> (-∞,-3)

see the attached figure to better understand the problem

5) Find the x-intercepts of the function

we know that

the x-intercepts are the values of x when the value of the function is equal to zero

In this problem the x-intercepts are

$(-6.61,0)$ and $(0.61,0)$

The function cross the x-axis twice

see the attached figure

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4 years ago

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