3r+n2−r+5−2n+2<span />=3r+n2+−r+5+−2n+2=3r+n2+−r+5+−2n+2<span />=(n2)+(−2n)+(3r+−r)+(5+2)<span />=n2+−2n+2r+7<span /><span />
=n2−2n+2r+7
6,050 before 6010 then 5080 after 5060 or basically any numbers that are greater than the one to the left of it :))
Answer:200
Step-by-step explanation:
The answer is A. It says that circle b is 16 times greater so yeah its A.
Answer:
72a
Step-by-step explanation: