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MrRa [10]
2 years ago
6

Work out an approximate solution to x^3+2x-1=0 use the iteration...... Help please!!!!?????

Mathematics
1 answer:
Kobotan [32]2 years ago
6 0

that's it's formulae for the appropriate root

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BlackZzzverrR [31]
The answer is (-10/3)
3 0
3 years ago
Read 2 more answers
How many hours are there in ten quarters of an hour?
svlad2 [7]

Answer:

2 1/2 hours

Step-by-step explanation:quarters means 1/4 and there are 4 of them in each hours  so if you have 10 quarters of a hour they add up to 2 hours and a half, because 2 hours times 4 equals 8 quarters and then add the other 2 quarters and you get half

6 0
3 years ago
Solve in radians help plz
PIT_PIT [208]
I think we can use the identity  sin x/2  = sqrt [(1 - cos x) /2]

cos x -  sqrt3 sqrt ( 1 - cos x) /sqrt2 = 1

cos x - sqrt(3/2) sqrt(1 - cos x) = 1
sqrt(3/2)(sqrt(1 - cos x) =  cos x - 1   Squaring both sides:-
1.5 ( 1 - cos x) = cos^2 x - 2 cos x + 1

cos^2 x - 0.5 cos x - 0.5 = 0 

cos x = 1 , -0.5

giving x = 0 , 2pi, 2pi/3,  4pi/3  ( for  0  =< x <= 2pi)

because of thw square roots some of these solutions may be extraneous so we should plug these into the original equations to see if they fit.

The last 2 results dont fit so the answer is  x = 0 , 2pi Answer
5 0
3 years ago
It is an unfair coin with unknown probability of head and tail. Can you generate even odds using this coin?
Vladimir79 [104]

Answer:

Yes, it can be generated if p = \frac{n}{n+1}, where n is a positive even integer.

Step-by-step explanation:

An odds for an event, is the probability or chance that this event will occur, divided by the probability that it will not occur.

Assume that the probability of getting tail when throwing the coin is p, therefore, the probability of getting a head is (1-p) and the odds for the event of getting tail is \frac{p}{1-p}.

If k is a positive integer, and we assume that the odds of getting a tail are even, then:

\frac{p}{1-p} = 2k

p = 2k - 2kp

p = \frac{2k}{2k+1}

Conclusion: if p = \frac{2k}{2k+1}, for some positive integer k, even odds are generated. For example: p = 2/3, 4/5, 6/7, ...

6 0
3 years ago
PLEASE ANSWER!!! I WILL MARK YOU AS BRAINLIEST!!!! An object is launched straight up into the air with an initial velocity of 40
Lana71 [14]

Answer:

6.7 seconds

Step-by-step explanation:

Let's calculate the maximum height covered by the object

Max height= U²Sin²tita/2g

Where g is acceleration due to gravity

Max height= 40²(sin90)²/(2*9.81)

Max height= 1600/19.62

Max height=81.55 m

Total max height= 30+81.55

Total max height= 111.55 m

Time t it will take to travel from the max height at acceleration of 4.9 m/s²

S= ut + ½at²

u= 0 at Mac height

S= 111.5 m

111.5 = ½(4.9)t²

223/4.9= t²

45.5= t²

6.745 seconds= t

6.7 seconds= t

5 0
3 years ago
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