Question

B) y = log2 (4" - 4) find the inverse of this equation

Answer 1

Answer:

$y = \frac{1}{4} \times {2}^{x} - 1$

Step-by-step explanation:

Assuming the given logarithmic equation is

$y = \log_{2}( {4}{x } - 4)$

We interchange x and y to get:

$x= \log_{2}( {4}{y} - 4)$

We solve for y now:

${2}^{x} = {4}{y} - 4$

We add 4 to both sides to get;

${2}^{x} + 4 = 4y$

Divide through by 4:

$y = \frac{1}{4} \times {2}^{x} - 1$