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erastovalidia [21]
3 years ago
5

Write a numerical expression for the difference of 100 and x

Mathematics
1 answer:
frosja888 [35]3 years ago
5 0

Answer:

100-x

Step-by-step explanation:

Hope this helps:)

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A group of students must collect at least $150 to organize a science fair. They have already collected $30. Which graph best rep
Mama L [17]
The answer is

A. Number line graph with closed circle on 120 and shading to the right.

100% Verified

Hope This Helps!:)

7 0
3 years ago
Solve the system of equations:
iVinArrow [24]

(-1,-2) \:  \:  \:  \:  \: and \:  \:  \:  \:  \: (3,6) \\ Answer: A

Step-by-step explanation:

y = 2x \\ y =  {x}^{2}  - 3 \\  \\ 2x =  {x}^{2}  - 3 \\  {x}^{2}  - 2x - 3 = 0 \\ (x + 1)(x - 3) = 0 \\ x + 1 = 0 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: x - 3 = 0 \\ x =  - 1 \:  \:  \:  \:  \: or \:  \:  \:  \:  \: x = 3

When x = -1

Substitute x = -1 into y = 2x

y = 2(-1)

y = -2

( -1, -2)

When x = 3

Substitute x = 3 into y = 2x

y = 2(3)

y = 6

( 3, 6)

5 0
3 years ago
HELP!! joels apartment building is 42 ft tall and casts a shadow of 20ft. If Joel is 6 ft tall, how long is his shadow
zhenek [66]

Step-by-step explanation:

an object and its shadow create a right-angled triangle.

2 objects and their shadows create 2 similar right-angled triangles.

that means the angles are the same, and the side lengths of one triangle all correlate with the corresponding side lengths of the other triangle via the same factor.

so,

42 × f = 6

f = 6/42 = 1/7

the length of Joel's shadow is then

20 × f = 20 × 1/7 = 2.857142857... ft

5 0
2 years ago
Which have smaller angles than 8
musickatia [10]

Answer:

6, 4, 3 and 1

7 0
2 years ago
Read 2 more answers
Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Lable any relative extrema, points of inflection, a
Anit [1.1K]

Answer:

Analyzed and Sketched.

Step-by-step explanation:

We are given y=\frac{\ln\left(5x)}{x^2}

To sketch the graph we need to find 2 components.

1) First derivative of y with respect to x to determine the interval where function increases and decreases.

2) Second derivative of y with respect to x to determine the interval where function is concave up and concave down.

y'=\frac{1-2\ln\left(5x)}{x^3}=0

x = \sqrt e/5 is absolute maximum

y''=\frac{6\ln\left(5x)-5}{x^4}=0

x=e^{5/6}/5 is the point concavity changes from down to up.

Here, x = 0 is vertical asymptote and y = 0 is horizontal asymptote.

The graph is given in the attachment.

4 0
3 years ago
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