Xy 14
x + y = -4
x + y = -4
x - x + y = -x - 4
y = -x - 4
xy = 14
x(-x - 4) = 14
x(-x) - x(4) = 14
-x² - 4x = 14
-x² - 4x - 14 = 0
-1(x²) - 1(4x) - 1(14) = 0
-1(x² + 4x + 14) = 0
-1 -1
x² + 4x + 14 = 0
x = -(4) ± √((4)² - 4(1)(14))
2(1)
x = -4 ± √(16 - 56)
2
x = -4 ± √(-40)
2
x = -4 ± 2i√(10)
2
x = -2 ± i√(10)
x + y = -4
-2 ± i√(10) + y = -4
- (-2 ± i√(10)) - (-2 ± i√(10))
y = -2 ± i√(10)
(x, y) = (-2 ± √(10), -2 ± √(10))
The two numbers that multiply to 14 and add up to -4 are -2 ± i√(10).
Answer: 615
Step-by-step explanation: you take the 45 times 12 months plus the 75 for the one time fee.
(2,1) i believe (?)
(4,5) (0,-3)
you add the x’s so the 4 and the 0 which is 4 then you divide it by 2 since there are two x numbers. for the y you would do the same 5+-3 ( plus and a minus makes a minus, 5-3) which is 2 then divide it by 2 again. Finally you get (2,1)
Answer:
25.1327cm
Step-by-step explanation:
C= 2πr
C=2π(4)
C=25.13274122
Answer: 6x
Work Shown:
For each step, the logs are all base b. This is to save time and hassle of writing tricky notation of having to write the smaller subscript 'b' multiple times. The first rule to use is that log(x^y) = y*log(x) for any base of a logarithm. The second rule is that 
meaning that the log base of itself is 1
log(b^(6x)) = 6x*log(b) .... pull down exponent using the first rule above
log(b^(6x)) = 6x*1 .... use the second rule mentioned
log(b^(6x)) = 6x
