<span>((x+deltaX)^2+x+deltaX-(x^2+x))/deltaX = (x^2 + 2x delta x + (delta x)^2 + x + delta x - x^2 - x) / delta x = delta x (2x + delta x + 1) / delta x = 2x + delta x + 1
Therefore, </span>Lim as x tends to 0 of <span>((x + delta X)^2 + x + deltaX - (x^2 + x)) / deltaX</span> = 1 + delta x
The length of the rectangle is x and the height is x-2
To find the area of a rectangle you multiply length times width
l(w) = 146
x(x-2) = 146
x^2 - 2x = 146
The formula is
(theta)/360 · 2(pi)r
theta is the given angle
r is radius of the circle
Answer:
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Step-by-step explanation:
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