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asambeis [7]
3 years ago
5

Rationalize

tle="1 \div \sqrt{}3 - \sqrt{2} " alt="1 \div \sqrt{}3 - \sqrt{2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

1 \div \sqrt{}3 - \sqrt{2}

\frac{1 -  \sqrt{2} \sqrt{3}  }{ \sqrt{3} }

\frac{(1 -  \sqrt{6}) \sqrt{3}  }{ \sqrt{3} \sqrt{3}  }

\frac{ \sqrt{3}  -  \sqrt{6 \times 3} }{3}

\frac{ \sqrt{3} -  3\sqrt{2}  }{3}

is a required answer.

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If f (n)= - 3n + 2, what is the value of f(12) ?
Gemiola [76]

f (n)= - 3n + 2

f(12) =-3(12)+2

= -36+2

= -34

3 0
3 years ago
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What are the vertical asymptotes of the function f(x) = 4x+8/x^2+3x-4
Yuri [45]

Answer:

<em>1 and -4</em>

Step-by-step explanation:

<em>The vertical asymptote of a function is gotten by equating the denominator of such function to zero.</em>

Given

f(x) = 4x+8/x^2+3x-4

The vertical asymptotes is expressed as;

x^2+3x-4 = 0

Factorize

x^2+4x-x-4 = 0

x(x+4) -1 (x+4) = 0

(x-1)(x+4) = 0

x-1 = 0 and x+4 = 0

x = 1 and x = -4

<em>Hence the vertical asymptotes of the function are 1 and -4</em>

4 0
3 years ago
Evaluate.<br><br><br><br> (12−2)+12 plz help i am having issues
cestrela7 [59]

Well this is easy. FOIL will help later on. For now (12-2) equals 10. Then add 12 and you get 22.

Brainliest answer you will see.

7 0
3 years ago
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Help on functions please.
dedylja [7]
A) Sub g(x) and h(x) into the equation:
x^2 + 3x - 40 - (-x -3)
= x^2 + 3x - 40 +x + 3
= x^2 + 4x - 37
Find x:
x= 4.40 and x= -8.40
b) Sub f(x) and g(x) into the equation: 
(x^2 - 64) / (x^2 + 3x -40)
= ((x+8) x (x-8)) / ((x+8) x (x-5))
= (x - 8) / (x-5)
Find x:
x= 8 and x = 5
How to get those number:
(x^2 - 64) = x^2 - 8^2 = (x-8) x (x+8)
( x^2 + 3x - 40) = (x^2 + +8x - 5x - 40) = x( x + 8) - 5( x + 8) = (x-5) x (x+8)

Try to do c and d :)
3 0
4 years ago
A store has a pair of pants marked $39.99 with a 40% off tag. What is the sale price of the pants?
Len [333]

Answer:

$23.99

Step-by-step explanation:

5 0
3 years ago
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