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asambeis [7]
3 years ago
5

Rationalize

tle="1 \div \sqrt{}3 - \sqrt{2} " alt="1 \div \sqrt{}3 - \sqrt{2} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

1 \div \sqrt{}3 - \sqrt{2}

\frac{1 -  \sqrt{2} \sqrt{3}  }{ \sqrt{3} }

\frac{(1 -  \sqrt{6}) \sqrt{3}  }{ \sqrt{3} \sqrt{3}  }

\frac{ \sqrt{3}  -  \sqrt{6 \times 3} }{3}

\frac{ \sqrt{3} -  3\sqrt{2}  }{3}

is a required answer.

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AlekseyPX

Answer:

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Step-by-step explanation:

1.

(-4)(-9)\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=4\times\:9\\= 36

2.

(-4)(9)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=-4\times\:9\\\\\mathrm{Multiply\:the\:numbers:}\:4\times\:9=36\\=-36

3.

(6)(6)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=6\times\:6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times\:6\\=36

4.

(-6)(-6)\\\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=6\times 6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times\:6\\=36

5.

(6)(-6)\\\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=-6\times 6\\\\\mathrm{Multiply\:the\:numbers:}\:6\times \:6=36\\=-36

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