Answer:
<em>1 and -4</em>
Step-by-step explanation:
<em>The vertical asymptote of a function is gotten by equating the denominator of such function to zero.</em>
Given
f(x) = 4x+8/x^2+3x-4
The vertical asymptotes is expressed as;
x^2+3x-4 = 0
Factorize
x^2+4x-x-4 = 0
x(x+4) -1 (x+4) = 0
(x-1)(x+4) = 0
x-1 = 0 and x+4 = 0
x = 1 and x = -4
<em>Hence the vertical asymptotes of the function are 1 and -4</em>
Well this is easy. FOIL will help later on. For now (12-2) equals 10. Then add 12 and you get 22.
Brainliest answer you will see.
A) Sub g(x) and h(x) into the equation:
x^2 + 3x - 40 - (-x -3)
= x^2 + 3x - 40 +x + 3
= x^2 + 4x - 37
Find x:
x= 4.40 and x= -8.40
b) Sub f(x) and g(x) into the equation:
(x^2 - 64) / (x^2 + 3x -40)
= ((x+8) x (x-8)) / ((x+8) x (x-5))
= (x - 8) / (x-5)
Find x:
x= 8 and x = 5
How to get those number:
(x^2 - 64) = x^2 - 8^2 = (x-8) x (x+8)
( x^2 + 3x - 40) = (x^2 + +8x - 5x - 40) = x( x + 8) - 5( x + 8) = (x-5) x (x+8)
Try to do c and d :)
Answer:
$23.99
Step-by-step explanation: