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wariber [46]
2 years ago
11

Fill in the blank !! question in picture below i have no clue what to do

Mathematics
1 answer:
Brilliant_brown [7]2 years ago
4 0
(tanx)^2

Proof:

Verify the following identity:
(sec(x) - 1) (sec(x) + 1) = tan(x)^2

Write secant as 1/cosine and tangent as sine/cosine:
(1/cos(x) - 1) (1/cos(x) + 1) = ^? (sin(x)/cos(x) )^2 

(sin(x)/cos(x))^2 = (sin(x)^2)/(cos(x)^2):
(1/cos(x) - 1) (1/cos(x) + 1) = ^?(sin(x)^2)/(cos(x)^2)

Put 1/cos(x) - 1 over the common denominator cos(x): 1/cos(x) - 1 = (1 - cos(x))/cos(x):
(1 - cos(x))/cos(x) (1/cos(x) + 1) = ^?(sin(x)^2)/(cos(x)^2)

Put 1/cos(x) + 1 over the common denominator cos(x): 1/cos(x) + 1 = (cos(x) + 1)/cos(x):
(1 - cos(x))/cos(x) (cos(x) + 1)/cos(x) = ^?(sin(x)^2)/(cos(x)^2)

((1 - cos(x)) (cos(x) + 1))/(cos(x) cos(x)) = ((1 - cos(x)) (cos(x) + 1))/cos(x)^2:
((1 - cos(x)) (cos(x) + 1))/(cos(x)^2) = ^?(sin(x)^2)/(cos(x)^2)

Multiply both sides by cos(x)^2:
(1 - cos(x)) (cos(x) + 1) = ^?sin(x)^2

(1 - cos(x)) (cos(x) + 1) = 1 - cos(x)^2:
1 - cos(x)^2 = ^?sin(x)^2

sin(x)^2 = 1 - cos(x)^2:
1 - cos(x)^2 = ^?1 - cos(x)^2

The left-hand side and right-hand side are identical:
Answer: (identity has been verified)

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Answer:

About 0.559 seconds

Step-by-step explanation:

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Where h_0 is the initial height of the book, which is 5, so we can write:

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Now, we want time it took for the book to reach ground (h = 0)

So, we substitute h = 0 and solve for t:

h=-16t^2+5\\0=-16t^2+5\\16t^2=5\\t^2=0.3125\\t=0.5590\\t=0.559

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5 0
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Answer:

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Step-by-step explanation:

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\frac{15-3}{3(5-3)}

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8x−7y=−5
Add 7y to both sides
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7 0
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