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Lapatulllka [165]
3 years ago
14

(x+4)(x^2-5x+3) multiply the polynomials

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0

9514 1404 393

Answer:

  x^3 -x^2 -17x +12

Step-by-step explanation:

Use the distributive property and collect terms.

   (x +4)(x^2 -5x +3) = x(x^2 -5x +3) +4(x^2 -5x +3)

  = x^3 -5x^2 +3x +4x^2 -20x +12

  = x^3 -x^2 -17x +12

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What is 10 to the third power x 1,579 pls show work
monitta
10^3= 1000
Therefore 1000x1579
= 1579000
7 0
3 years ago
Read 2 more answers
Which sequence of transformations means the image would be congruent to the original figure instead of similar to it?
Gnom [1K]

Answer:

B.) translation and rotation

Step-by-step explanation:

3 0
3 years ago
1. Find the HCF of the following numbers by prime factorisation and continued division method10,35,40​
statuscvo [17]

Answer:

Step-by-step explanation:

10 = 2*5

35 = 5*7

40 = 2*2*2*5

The number 5 is common to all three  factorisations

So the HCF = 5.

Continued division:

10 and 35:

 10) 35(3

       30

          5)10(2

              10

                0

- so the HCF of 10 and 35 is 5.

10 and 40:

10)40( 4

     40

        0  

So the HCF of 10 and 40 is 10

We found HCF of 10 and 35 is 5 so:

HCF of 10, 35 and 40 is HCF of 5 and 10 which is 5.  

4 0
3 years ago
The population of the town is 2500 and is decreasing at a rate of 3% per year. determine the population after 11 years
Debora [2.8K]

Answer:

\huge \boxed{ \boxed{1675}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • percent
  • percentage words problem
  • PEMDAS
<h3>given:</h3>
  • population:2500
  • decreasing rate:3%
<h3>to find:</h3>
  • the population after 11 years
<h3>let's solve:</h3>

according to the question

population decreases in 1 year

2500 \times 3\% \\ 2500 \times  \frac{3}{100}  \\ 25 \times 3 \\ 75

population will decrease in 11 years

  • 75×11
  • 825

so the population of the town after 11 years will be

2500-825

<h2>1675</h2>
4 0
3 years ago
Find the measures of the angles formed by (a) two consecutive radii and (b) a radius and a side of the given regular polygon.14.
Bezzdna [24]

Answer:

Step-by-step explanation:

Let radius = r and side of a regular polygon = s

a) The consecutive radii = r + r + 1

i) For Square ( 4- sides) : r + r + 1 = 90°

2r + 1 = 90°

ii) For Pentagon (5- sides) :  2r + 1 =108°

iii) For Hexagon (6- sides): 2r + 1 = 120°

iv) For Heptagon (7- sides): 2r + 1 = 129°

v) For Octagon (8- sides): 2r + 1 = 135°

vi) For Nonagon (9- sides): 2r + 1 = 140°

vii) For 20 sides: 2r + 1 = 162°

b) A radius and a side = r + s

i) For Square (4- sides): r + s = 90°

ii ) For Pentagon (5- sides): r + s = 108°

iii) For Hexagon (6- sides): r + s = 120°

iv) For Heptagon (7- sides): r + s = 129°

v) For Octagon (8- sides): r + s = 135°

vi) For Nonagon (9- sides): r + s = 140°

vii) For 20 sides: r + s = 162°

5 0
3 years ago
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