This sequence be represented as a recursive equation by a1=8 and an=2a1
<u>Step-by-step explanation</u>:
- 'Recursive' refers to the repetition of a specific process in a sequence.
- The given sequence is {8,16,32,64}.
- If the value is 2 times the previous value, then an=2a(n-1)
Let a1=8,
then a2 = 2a(2-1)
⇒ a2 = 2a1
⇒ a2 = 2(8)
⇒ a2 = 16
Similarly,
For a2=16,
⇒ a3 = 2(a2)
⇒ a3 = 2(16)
⇒ a3 = 32
For a3=32,
⇒ a4 = 2(a3)
⇒ a4 = 2(32)
⇒ a4 = 64
∴ The equation is recursive as a1=8 and an=2a1 to follow the sequence.
Answer:
x = 13
Step-by-step explanation:
Take the square root of both sides
Answer:
(x+8) ^2=64
Step-by-step explanation:
that will give you your two solutions: x= -16 and x=0. I hope this helps!!!
20/28 = 3x / (4x + 2)
84x = 20(4x + 2)
84x - 80x = 40
4x = 40
x = 10
so the 2 lines are equal to 30 and 42
We can factor this by using grouping. Take the leading coefficient and multiply it by the constant. In this case we get 5*-7 = -35.
Now we need 2 numbers that add to 2 and multiply to be -35. The numbers are -5 and 7.
So split the 2r into these two terms and group.
(5r^2 - 5r) + (7r - 7)
Factor both groups.
5r(r-1) + 7(r-1)
The factors of (r-1) can be added together to get the answer.
(r-1)(5r+7)
